A rectangular waveguide has dimensions 1 cm × 0.5 cm. Its cut off frequency is : 

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NIELIT Scientific Assistant ECE 5 Dec 2021 Official Paper
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  1. 10 GHz
  2. 15 GHz
  3. 5 GHz
  4. 2.5 GHz

Answer (Detailed Solution Below)

Option 2 : 15 GHz
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Concept:

The cut-off frequency of a rectangular waveguide in dominant TE10 mode is given by:

\( f_c = \frac{c}{2a} \), where:

c = speed of light = \( 3 \times 10^8~m/s \), and a = broader dimension of the waveguide

Calculation:

Given:

Dimensions of waveguide = 1 cm × 0.5 cm

So, a = 1 cm = 0.01 m

Using the formula, \( f_c = \frac{3 \times 10^8}{2 \times 0.01} \)

\( f_c = \frac{3 \times 10^8}{0.02} = 1.5 \times 10^{10}~Hz = 15~GHz \)

Correct Answer: 2) 15 GHz

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