Question
Download Solution PDFA certain sum becomes 3 times itself in 6 years at a simple interest. The number of years in which it becomes 9 times itself is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A certain sum becomes 3 times itself in 6 years at simple interest.
Principal (P) = ₹X
Amount after 6 years (A) = ₹3X
Time for 3X = 6 years
Amount after unknown time (t) = ₹9X
Formula used:
Simple Interest (SI) = P × r × t / 100
Total Amount (A) = P + SI
Calculation:
For 3X:
SI = A - P
⇒ ₹3X - ₹X = ₹2X
SI = ₹2X
Using SI formula:
₹2X = ₹X × r × 6 / 100
⇒ r = (2 × 100) / 6
⇒ r = 33.33%
For 9X:
SI = ₹9X - ₹X
⇒ SI = ₹8X
Using SI formula:
₹8X = ₹X × r × t / 100
⇒ t = (8 × 100) / 33.33
⇒ t ≈ 24 years
∴ The correct answer is option (4).
Last updated on Jun 5, 2025
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