Simple Interest MCQ Quiz - Objective Question with Answer for Simple Interest - Download Free PDF

Last updated on May 24, 2025

Attempt these Simple Interest MCQs Quiz to help you practise for the Quantitative Aptitude sections. This will help you clear Bank PO, IBPS PO, SBI PO, RRB PO, RBI Assistant, LIC,SSC, MBA - MAT, XAT, CAT, NMAT, UPSC, NET and more. The Simple Interest Objective Questions include those that have been frequently asked and are important. Your final target should be to solve all the Simple Interest Question Answers with 80% and more accuracy.

Latest Simple Interest MCQ Objective Questions

Simple Interest Question 1:

A principal amount of ₹1200 grows to ₹1440 in 2 years. Calculate the rate of interest.

  1. 10%
  2. 12%
  3. 15%
  4. 8%

Answer (Detailed Solution Below)

Option 1 : 10%

Simple Interest Question 1 Detailed Solution

Given:

Principal (P) = ₹1200

Amount (A) = ₹1440

Time (t) = 2 years

Formula Used:

Simple Interest (SI) = A - P

SI = \(\dfrac{P \times r \times t}{100}\)

Where, r = rate of interest

Calculations:

SI = \(\dfrac{P \times r \times t}{100}\):

240 = \(\dfrac{1200 \times r \times 2}{100}\)

⇒ 240 = 12 × r × 2

⇒ 240 = 24 × r

⇒ r = \(\dfrac{240}{24}\)

⇒ r = 10%

∴ The rate of interest is 10% per annum.

Simple Interest Question 2:

A principal amount earns Rs. 420 as simple interest at an annual rate of 10% over 2 years. Calculate the principal amount.

  1. 2000 Rs
  2. 2100 Rs
  3. 4200 Rs
  4. 1900 Rs

Answer (Detailed Solution Below)

Option 2 : 2100 Rs

Simple Interest Question 2 Detailed Solution

Given:

Simple Interest (SI) = ₹420

Annual Rate of Interest (R) = 10%

Time (T) = 2 years

Formula Used:

Simple Interest (SI) = (Principal (P) × Rate (R) × Time (T)) / 100

To find the Principal (P), rearrange the formula: P = (SI × 100) / (R × T)

Calculation:

P = (420 × 100) / (10 × 2)

P = 42000 / 20

P = 2100

∴ The principal amount is ₹2100.

Simple Interest Question 3:

If a certain principal amounts to Rs. 34,000 in 3 years and to Rs. 40,000 in 5 years at a simple interest of r% per year, then r =

  1. 8
  2. 15
  3. 10
  4. 12

Answer (Detailed Solution Below)

Option 4 : 12

Simple Interest Question 3 Detailed Solution

Given:

Amount after 3 years = ₹34,000

Amount after 5 years = ₹40,000

Time difference = 5 - 3 = 2 years

Formula used:

Simple Interest = P × r × t / 100

Difference in amount = Interest for 2 years

Calculation:

Interest for 2 years = 40000 - 34000 = ₹6000

⇒ Interest for 1 year = 6000 / 2 = ₹3000

Now, Principal = 34000 - (3000 × 3) = 34000 - 9000 = ₹25000

Using SI formula:

SI = (25000 × r × 1)/100 = 3000

⇒ (25000 × r)/100 = 3000

⇒ 250r = 3000

⇒ r = 12

∴ The correct answer is r = 12%

Simple Interest Question 4:

A memorial trust donates Rs.10,00,000 to a school, the interest on which is to be used for awarding 3 scholarships to students obtaining first three positions in the school examination every year. If the donation earns an interest of 12 per cent per annum and the values of the second and third scholarships are Rs. 40,000 and Rs. 25,000 respectively, find out the value of the first scholarship.

  1. Rs. 55,000
  2. Rs. 60,000
  3. Rs. 50,000
  4. Rs. 65,000

Answer (Detailed Solution Below)

Option 1 : Rs. 55,000

Simple Interest Question 4 Detailed Solution

Given:

Donation = ₹10,00,000

Rate of Interest (r) = 12% per annum

Scholarship 2 = ₹40,000

Scholarship 3 = ₹25,000

Formula used:

Total Interest = Scholarship 1 + Scholarship 2 + Scholarship 3

Total Interest = Donation × Rate of Interest

Calculation:

Total Interest = ₹10,00,000 × (12/100)

⇒ Total Interest = ₹1,20,000

Total Interest = Scholarship 1 + ₹40,000 + ₹25,000

⇒ ₹1,20,000 = Scholarship 1 + ₹65,000

⇒ Scholarship 1 = ₹1,20,000 - ₹65,000

⇒ Scholarship 1 = ₹55,000

∴ The correct answer is option (1).

Simple Interest Question 5:

Simple interest at 8% rate of interest for 10 years is Rs. 17600. Find the principle?

  1. 24000
  2. 25000
  3. 22000
  4. 26000
  5. 32000

Answer (Detailed Solution Below)

Option 3 : 22000

Simple Interest Question 5 Detailed Solution

Given:

Rate of interest (r) = 8%

Time (t) = 10 years

Simple Interest (SI) = ₹17,600

Formula used:

SI = P × r × t / 100

Calculations:

17600 = P × 8 × 10 / 100

⇒ 17600 = P × 80 / 100

⇒ 17600 = P × 0.8

⇒ P = 17600 / 0.8

⇒ P = ₹22,000

∴ The principal is ₹22,000.

Top Simple Interest MCQ Objective Questions

A sum of money invested at a certain rate of simple interest per annum amounts to Rs. 14,522 in seven years and to Rs. 18,906 in eleven years. Find the sum invested (in Rs.). 

  1. 6850
  2. 6900
  3. 6800
  4. 6750

Answer (Detailed Solution Below)

Option 1 : 6850

Simple Interest Question 6 Detailed Solution

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Given: 

Amount produce in 7 years = Rs.14522

Amount produce in 11 years = Rs.18906

Formula used:

Simple interest (S.I) = (P × R × T)/100

Calculation:

Amount produce in 7 years = Rs.14522

Amount produce in 11 years = Rs.18906

S.I produced in (11 - 7) = 4 years = (18906 - 14522) = Rs.4384

S.I in 1 years = 4384/4 = 1096

Principal = 14522 - (1096 × 7)

⇒ (14522 - 7672) = Rs.6850

∴ The correct answer is Rs.6850.

A sum becomes Rs. 10650 in 5 years. and Rs. 11076 in 6 years at simple interest. What is the sum?

  1. Rs. 8946
  2. Rs. 8740
  3. Rs. 8520
  4. Rs. 8800

Answer (Detailed Solution Below)

Option 3 : Rs. 8520

Simple Interest Question 7 Detailed Solution

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Concept Used:

In this type of question, number can be calculated by using the below formulae

Formula Used:

If a sum with simple interest rate, amounts to Rs. ‘A’ in y years. and Rs. ‘B’ in z years. then,

P = (A × z – B × y)/(z – y)

Calculation:

Using the above formulae, we have

P = (10650 × 6 – 11076 × 5)

P = Rs. 8520

Required principal is Rs. 8520 

Alternate Method Sunny 28.7.21 

A sum becomes Rs. 10650 in 5 years. and Rs. 11076 in 6 years. at simple interest

Interest of 1 year = 11076 – 10650 = Rs. 426

Interest of 5 year = 426 × 5 = 2130

∴ Required principal = 10650 – 2130 = Rs. 8520

What is the difference (in Rs.) between the simple interest and the compound interest on a sum of Rs. 8000 for \(2\frac{2}{5}\) years at the rate of 10% p.a. when the interest is compounded yearly?

  1. 152.80
  2. 150
  3. 155
  4. 147.20

Answer (Detailed Solution Below)

Option 4 : 147.20

Simple Interest Question 8 Detailed Solution

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Given:

Principal = Rs. 8000

Rate = 10%

Time =  \(2\frac{2}{5}\) years

Formula used:

SI = (P × t × r)/100

CI = P(1 + r/100)t - P

P = Principal

t = time

r = rate

Calculation:

SI = (8000 × 12 × 10)/(100 × 5)

⇒ Rs. 1920

CI = 8000[1 + 10/100]2 × [1 + 4/100] - 8000

⇒ 8000 × 11/10 × 11/10 × 26/25 - 8000

⇒ 10067.2 - 8000

⇒ 2067.2

Difference = 2067.2 - 1920 = 147.2

∴ Required difference is Rs. 147.2

Shortcut Trick qImage65f494db3692bb77a5668945

So, the difference of CI and SI = 80 + 32 + 32 + 3.2

∴ The Difference of CI and SI = 147.2.

A sum of money at simple interest doubles in 10 years. In how many years, at the same rate, will it be tripled?

  1. 30 years
  2. 25 years
  3. 20 years
  4. 15 years

Answer (Detailed Solution Below)

Option 3 : 20 years

Simple Interest Question 9 Detailed Solution

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Given:

Amount = 2P

Time = 10 years

Formula used:

SI = (PRT/100) 

Amount = (PRT/100) + P

Calculation:

Amount = (PRT/100) + P

2P = (PR/10) + P 

⇒ P = (PR/10) 

⇒ R = 10%

According to the question, Amount = 3P

3P = (10PT/100) + P 

⇒ 2P = (PT/10)

⇒ T = 20 years

 ∴ Time taken to triple the amount is 20 years.

Shortcut TrickInterest = 2P - P = P = 100% of principle

Time = 10 year

Hence, rate = Interest/Time = 100/10 = 10%

New interest = 3P - P = 2P = 200% of principle

∴ Time = Interest/Rate = 200/10 = 20 Years

A sum of money was invested at the rate of 7.5% simple interest per annuum for 4 years. If the investments were for 5 years, the interest earned would have been Rs. 375 more. What was the initial sum invested?

  1. Rs. 4,500
  2. Rs. 5,000
  3. Rs. 3,750
  4. Rs. 4,750

Answer (Detailed Solution Below)

Option 2 : Rs. 5,000

Simple Interest Question 10 Detailed Solution

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Interest earned for 5 years – Interest earned for 4 years = 375

Let the principal be Rs. P,

⇒ (P × 7.5 × 5) /100 – (P × 7.5 × 4) /100 = 375

⇒ (37.5 × P) /100 – (30 × P) /100 = 375

⇒ (7.5 × P) /100 = 375

∴ P = Rs. 5000

A sum of money lent out at simple interest amounts to Rs. 715 after 3 years and to Rs. 990 after a further period of 5 years. Find the sum.

  1. Rs. 550
  2. Rs. 600
  3. Rs. 590
  4. Rs. 625

Answer (Detailed Solution Below)

Option 1 : Rs. 550

Simple Interest Question 11 Detailed Solution

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Given:

Amount after 3 years = Rs. 715

Amount after 8 years  = Rs. 990

Formula used:

A = P + SI

Where A = amount , P = Principle

And SI = Simple interest

Calculation:

Amount in 3 years = Rs. 715

Now it is given in the question, amount for the time of further 5 years i.e 

Total time = 5 years + 3 years = 8 years.

Amount in 8 years = Rs. 990

SI for 5 years = Amount after 8 years  - Amount after 3 years

⇒ SI for 5 years = 990 - 715 = 275

SI for 1 years = 275/5 = 55

SI for 3 years = 55 × 3 = Rs.165

P = Amount of 3 years - SI of 3 years

⇒ P = 715 - 165 = 550

∴  The sum is Rs. 550

Confusion Points It is given in the question that after further 5 years amount is calculated , so total time will be (5 +3) years = 8 years. not 5 years.

Simple interest on a sum of money for 5 years is \(\frac{2}{5}\) times the principal, the rate for simple interest is 

  1. 13%
  2. \(12\frac{1}{3}\% \)
  3. \(14\frac{1}{3}\% \)
  4. \(8\% \)

Answer (Detailed Solution Below)

Option 4 : \(8\% \)

Simple Interest Question 12 Detailed Solution

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Let P = principal, R = rate of interest and N = time period

Simple interest = PNR/100

Given,

N = 5 years​

Then,

⇒ 2/5 × P = (P × R × 5)/100

⇒ R = 200/25

\(\therefore {\rm{\;}}R = 8 % \) %

The simple interest on a sum for 6 years is Rs. 29250. The rate of interest for the first 2 years is 7 percent per annum and for the next 4 years is 16 percent per annum. What is the sum?

  1. Rs. 36600
  2. Rs. 37500
  3. Rs. 35400
  4. Rs. 38300

Answer (Detailed Solution Below)

Option 2 : Rs. 37500

Simple Interest Question 13 Detailed Solution

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Given:

The simple interest for 6 years on a sum = 29250

Formula used:

\(SI\ =\ {P\ \times R\ \times T \over 100}\)     (Where SI = Simple interest, P = Principle, R = The rate, and T = The time)

Calculation:

Let us assume the sum be P

⇒ The simple interest for the first 2 years at a 7% rate = \(\ {P\ \times 7\ \times 2 \over 100}\ = {14P\over 100}\)

⇒ The simple interest for the next 4 years at a 16% rate = \(\ {P\ \times 16\ \times 4 \over 100}\ = {64P\over 100}\) 

⇒ The total simple interest = 29250

⇒ \({14P\over 100}\ +\ {64P\over 100}\ =\ 29250\)

\({78P\over 100}\ =\ 29250\)

⇒ By solving 

⇒ The required sum = P = 37500

∴ The required result will be 37500.

Find the simple interest on ₹2,700 for 8 months at 5 paise per rupee per month.

  1. ₹950
  2. ₹720
  3. ₹540
  4. ₹1,080

Answer (Detailed Solution Below)

Option 4 : ₹1,080

Simple Interest Question 14 Detailed Solution

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Given:

Principle = Rs. 2700

Time = 8 months = 8/12 year = 2/3 year

Rate of interest = 5 paisa per month = 5 × 12 paisa per year = 60 paisa per year = 60 %

Formula used:

SI = PRT/100

Calculation:

SI = (2700 × 60 × 2) / (100 × 3)

⇒ 9 × 120

⇒ 1080

∴ The SI will be Rs. 1080.

What is the simple interest on Rs. 32,000 at 8.5% per annum for period from 10th Feb., 2019 to 24th April, 2019?

  1. Rs. 550
  2. Rs. 555
  3. Rs. 544
  4. Rs. 540

Answer (Detailed Solution Below)

Option 3 : Rs. 544

Simple Interest Question 15 Detailed Solution

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Given:

Principle, P = Rs. 32,000

Rate, r = 8.5%

Time, t = (18 + 31 + 24) / 365 = 73 / 365 = 1 / 5 years

Concept used:

Simple Interest = (P × r × t) / 100

Calculation:

SI = (32,000 × 8.5 × 1 / 5) / 100

⇒ (32 × 85) / 5

⇒ 32 × 17

⇒ Rs. 544
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