A certain pulse measures 10 ms and has a period of 50 ms. The duty cycle is

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SDSC (ISRO) Technician B (Electronic Mechanic): Previous Year Paper (Held on 29 April 2018)
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  1. 5%
  2. 10%
  3. 20%
  4. 50%

Answer (Detailed Solution Below)

Option 3 : 20%
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Detailed Solution

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Concept:

The duty cycle for an alternating quantity describes the fraction of time that the pulse is ON in one pulse period.

Mathematically, this is defined as:

Duty Cycle = \(\frac{T_{on}}{T_{on}+T_{off}}\)

Ton = Time for which the output is ON

Toff = Time for which the output is OFF

Also, the Time period is the sum of the ON time and OFF time, i.e.

T = Ton + Toff

\(Duty~Cycle=\frac{T_{on}}{{T}}\)

Calculation:

With Ton = 10 ms, and T = 50 ms, the duty cycle will be:

\(Duty~Cycle=\frac{10}{{50}}=\frac{1}{5}\)

% Duty cycle will be:

\(\%D=\frac{1}{5}\times 100\)

%D = 20%

26 June 1

Periodic waveform with different duty cycles is as shown below:

F2 S.B Madhu 17.02.20 D6

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