Question
Download Solution PDFA, B and C run simultaneously, starting from a point, around a circular track of length 1200 m, at respective speeds of 2 m/s, 4 m/s and 6 m/s. A and B run in the same direction, while C runs in the opposite direction to the other two. After how much time will they meet for the first time?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Total track length = 1200 m
Speed of A = 2 m/s ; speed of B = 4 m/s
Speed of C = 6 m/s
Formula used:
Distance = relative speed × time
Calculation:
Relative speed of A and B = (4 - 2) = 2 m/s
Relative speed of B and C = (6 + 4) = 10 m/s
Relative speed of A and C = (6 + 2) = 8 m/s
Time taken by A and B = 1200/2 = 600 sec
Time taken by B and C = 1200/10 = 120 sec
Time taken by A and C = 1200/8 = 150 sec
A, B and C will meet at = L.C.M {600,120, 150} = 600 sec = 600/60 = 10 minutes
∴ The correct answer is 10 minutes.
Last updated on Jun 9, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the SSC CGL exam form.
-> Candidates can refer to the SSC CGL syllabus for a better understanding of the exam structure and pattern.
-> The SSC CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.