Partial Speed MCQ Quiz - Objective Question with Answer for Partial Speed - Download Free PDF

Last updated on Jun 3, 2025

Testbook stages MCQ Quiz on Partial Speed, their solutions and explanations form an integral part of the Quantitative aptitude section of various competitive exams. Almost 2-3 questions are always asked from this Partial Speed in the exams. Candidates preparing for Government exams such as SSC, Bank, RRB, etc. must know that quantitative aptitude constitutes a major portion of the syllabus of these examinations. Read this article and find some interesting tips and tricks for the partial speed section.

Latest Partial Speed MCQ Objective Questions

Partial Speed Question 1:

Edwin completes a journey in 11 hrs. He travels first half of the journey at the rate of 20 km/hr and second half at the rate of 24 km/hr. Find the distance travelled in km.

  1. 200
  2. 220
  3. 260
  4. 240

Answer (Detailed Solution Below)

Option 4 : 240

Partial Speed Question 1 Detailed Solution

Given:

Edwin completes a journey in 11 hours.

First half of the journey speed = 20 km/hr

Second half of the journey speed = 24 km/hr

Formula used:

Total time = Time for the first half + Time for the second half

Distance = Speed × Time

Calculation:

Let the total distance = D km.

Distance for the first half = D/2 km

Distance for the second half = D/2 km

Time for the first half = Distance / Speed = \(\dfrac{D}{2×20}\)

Time for the second half = Distance / Speed = \(\dfrac{D}{2×24}\)

Total time = 11 hours

\(\dfrac{D}{2×20} + \dfrac{D}{2×24} = 11\)

\(\dfrac{D}{40} + \dfrac{D}{48} = 11\)

⇒ Taking LCM of 40 and 48 = 240

\(\dfrac{6D}{240} + \dfrac{5D}{240} = 11\)

\(\dfrac{11D}{240} = 11\)

⇒ D = 240

∴ The correct answer is option (4).

Partial Speed Question 2:

Q completes a journey in 33 hours. She travels first half of the journey at the rate of 30 kmph and second half at the rate of 36 kmph. Find the total distance of the entire journey? (in km)

  1. 980
  2. 1180
  3. 1280
  4. 1080

Answer (Detailed Solution Below)

Option 4 : 1080

Partial Speed Question 2 Detailed Solution

Given:

Q completes a journey in 33 hours.

First half of the journey speed = 30 kmph

Second half of the journey speed = 36 kmph

Formula used:

Total time = (Distance/Speed for first half) + (Distance/Speed for second half)

Let total distance = D, so first half distance = D/2

Calculations:

Total time = 33 hours

\(\dfrac{D/2}{30} + \dfrac{D/2}{36} = 33\)

\(\dfrac{D}{60} + \dfrac{D}{72} = 33\)

\(\dfrac{6D + 5D}{360}= 33\)

\(\dfrac{11D}{360} = 33\)

⇒ D = 3 × 360

⇒ D = 1080 km

∴ The correct answer is option (4).

Partial Speed Question 3:

A train travels from Kandla to Mahesana at a speed of 82 km/hr and returns at a speed of 84 km/hr. If it takes 166 hours for total travel, then find the distance between Kandla to Mahesana. (In km)

  1. 7888
  2. 6888
  3. 9888
  4. 5888

Answer (Detailed Solution Below)

Option 2 : 6888

Partial Speed Question 3 Detailed Solution

Given:

Speed from Kandla to Mahesana = 82 km/hr

Speed from Mahesana to Kandla = 84 km/hr

Total time = 166 hours

Formula used:

Total time = Time for forward journey + Time for return journey

Time = Distance / Speed

Calculation:

Let the distance between Kandla and Mahesana be D km.

Total time = (Distance / Speed forward) + (Distance / Speed return)

⇒ 166 = (D / 82) + (D / 84)

⇒ 166 = (84D + 82D) / (82 × 84)

⇒ 166 = (166D) / (82 × 84)

⇒ D = (166 × 82 × 84) / 166

⇒ D = 82 × 84

⇒ D = 6888 km

∴ The correct answer is option (2).

Partial Speed Question 4:

A person can complete a journey in 9 hours. He covers the first one-third part of the journey at the rate of 35 km/h and the remaining distance at the rate of 28 km/h. What is the total distance (in km) of his journey?

  1. 270
  2. 268
  3. 277
  4. 275

Answer (Detailed Solution Below)

Option 1 : 270

Partial Speed Question 4 Detailed Solution

Given:

A person can complete a journey in 9 hours.

First one-third of the journey at the rate of 35 km/h.

Remaining two-thirds of the journey at the rate of 28 km/h.

Formula used:

Distance = Speed × Time

Total time = Time for first one-third + Time for remaining two-thirds

Calculation:

Total time = 9 hours

Let total distance = D km

Distance for first one-third = \(\frac{D}{3}\)

Distance for remaining two-thirds = \(\frac{2D}{3}\)

Time for first one-third = \(\frac{\frac{D}{3}}{35}\)

Time for remaining two-thirds = \(\frac{\frac{2D}{3}}{28}\)

Total time = \(\frac{\frac{D}{3}}{35} + \frac{\frac{2D}{3}}{28}\)

⇒ 9 = \(\frac{D}{105} + \frac{2D}{84}\)

⇒ 9 = \(\frac{4D}{420} + \frac{10D}{420}\)

⇒ 9 = \(\frac{14D}{420}\)

\(\frac{D}{30} = 9\)

⇒ D = 270 km

∴ The correct answer is option (1).

Partial Speed Question 5:

Kavya has to reach Bhopal which is 1011 km away in 19 hours. His starting speed for 7 hours was 25 km/hr. For the next 152 km his speed was 19km/hr. By what speed he must travel now so as to reach Bhopal in decided time of 19 hours?

  1. 167 km/hr
  2. 171 km/hr
  3. 177 km/hr
  4. 165 km/hr

Answer (Detailed Solution Below)

Option 2 : 171 km/hr

Partial Speed Question 5 Detailed Solution

Given:

Total distance to Bhopal = 1011 km

Total time to reach Bhopal = 19 hours

Calculation:

Journey Phase 1: Speed = 25 km/hr, Time = 7 hours

Distance covered in Phase 1 = Speed × Time = 25 km/hr × 7 hours = 175 km

Journey Phase 2: Distance covered = 152 km, Speed = 19 km/hr

Time taken in Phase 2 = Distance / Speed = 152 km / 19 km/hr = 8 hours

For the Remaining Journey:

Total distance covered so far = Distance in Phase 1 + Distance in Phase 2 = 175 km + 152 km = 327 km

Remaining distance to travel = Total distance - Total distance covered so far = 1011 km - 327 km = 684 km

Total time spent so far = Time in Phase 1 + Time in Phase 2 = 7 hours + 8 hours = 15 hours

Remaining time to reach Bhopal = Total time - Total time spent so far = 19 hours - 15 hours = 4 hours

Required speed for the remaining journey = Remaining distance / Remaining time

Required speed = 684 km / 4 hours = 171 km/hr

∴ Kavya must travel at a speed of 171 km/hr to reach Bhopal in the decided time.

Top Partial Speed MCQ Objective Questions

A car travels some distance at a speed of 8 km/hr and returns at a speed of 12 km/hr. If the total time taken by the car is 15 hours, then what is the distance (in km)?

  1. 48
  2. 60
  3. 56
  4. 72

Answer (Detailed Solution Below)

Option 4 : 72

Partial Speed Question 6 Detailed Solution

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Let the distance be d km.

We know that,

Distance = Speed x Time

\( \Rightarrow \;\frac{d}{8} + \frac{d}{{12}} = 15\)

\( \Rightarrow \;\frac{{3d + 2d}}{{24}} = 15\)

⇒ d = 72 km 

A car completes a journey in seven hours. It covered half of the distance at 40 kmph and the remaining half at 60 kmph speed. Then, the distance (in km) covered is:

  1. 280
  2. 300
  3. 336
  4. 420

Answer (Detailed Solution Below)

Option 3 : 336

Partial Speed Question 7 Detailed Solution

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Given data:

Total time of journey = 7 hours

Speed of car for half distance = 40 km/hr

Speed of car for remaining distance = 60 km/hr

Concept used:

Distance = Speed × Time

Calculation:

Let total distance be 2x.

Time1 = Distance/Speed

⇒ x/40 hours

Time2 = Distance/Speed

⇒ x/60 hours

Total time = Time1 + Time2

⇒ 7 = x/40 + x/60

⇒ 7 = (3x + 2x)/120

⇒ 7 = 5x/120

⇒ x = 7 × 24

⇒ x = 168 km

⇒ Total distance = 2x

⇒ 2 × 168

⇒ 336 km

∴ Total distance covered by the car is 336 km.

Alternate Method

Concept used:

Average speed = (2 × Speed1 × Speed2)/(Speed1 + Speed)

Calculation:

Since distance covered in both the cases is same we can apply concept of average velocity required to cover same distance.

Average speed = (2 × Speed1 × Speed2)/(Speed1 + Speed)

⇒ (2 × 40 × 60)/(40 + 60)

⇒ 4800/100

⇒ 48 km/hr

Distance = Speed × Time

⇒ 48 × 7

⇒ 336 km

∴ Total distance covered by the car is 336 km.

If Maya goes to office at a speed of 40 km/hr, she reaches 5 minutes late, If she travels at the speed of 60 km/hr, she is 10 minutes early. What is the distance to office from her home?

  1. 30 km
  2. 40 km
  3. 50 km
  4. 35 km

Answer (Detailed Solution Below)

Option 1 : 30 km

Partial Speed Question 8 Detailed Solution

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Given:

Maya goes to office at a speed of 40 km/hr, she reaches 5 minutes late.

Maya goes to office at a speed of 60 km/hr, she is 10 minutes early.

Formula Used:

Distance = Speed × Time

Calculation:

Let the original speed of Maya be x.

Let the distance to office from her home be D.

Maya goes to office at a speed of 40 km/hr, she reaches 5 minutes late.

⇒ D/40 - D/x = 5/60

⇒ D(1/40 - 1/x) = 1/12

⇒ D(x - 40/40x) = 1/12

⇒ D = 40x/12(x - 40)

Maya goes to office at a speed of 60 km/hr, she is 10 minutes early.

⇒ D/x - D/60 = 10/60

⇒D(60 - x)/60x = 1/6

⇒ 40x × (60 - x) /[12(x - 40) × 60x] = 1/6

⇒ 40x × (60 - x) × 6 = 12(x - 40) × 60x 

⇒ x = 45 km/hr

The distance = 40x/12(x - 40) = 40 × 45/12 × 5 = 30 km

∴ The distance to office from her home is 30 km.

Shortcut Trick 

Distance =  S1 × S2 × change in time(hr)/(S1 - S2)

Distance = 40 × 60 × (15/60)/(60 - 40) = 30 km

∴ The distance to office from her home is 30 km.

A car starts from point A towards point B, travelling at the speed of 20 km/h. 1\(\frac{1}{2}\)hours later, another car starts from point A and travelling at the speed of 30 km/h and reaches 2\(\frac{1}{2}\)hours before the first car. Find the distance between A and B.

  1. 300 km
  2. 240 km
  3. 260km
  4. 280 km

Answer (Detailed Solution Below)

Option 2 : 240 km

Partial Speed Question 9 Detailed Solution

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Given:

A car starts from point A towards point B, travelling at the speed of 20 km/h.

1\(\frac{1}{2}\)hours later, another car starts from point A and travelling at the speed of 30 km/h and reaches 2\(\frac{1}{2}\)hours before the first car.

Concept used:

Total distance = \(\frac{(S_1 × S_2)}{S_1-S_2} \times (T_1+T_2)\)

Here,

S1 = speed of the faster object

S2 = speed of the slower object

T1 = Time1

T2 = Time 2

Calculation:

According to the concept,

Total distance = \(\frac{(20 × 30)}{30-20} \times (1.5+2.5)\)

⇒ \(\frac{(600)}{10} \times 4\)

⇒ 240 km

∴ The distance between A and B is 240 km.

Alternate Method

Let the total distance be x km,

In 1.5 hr 1st car travel 30 km, remaining (x - 30) km

So, according to the question.

⇒ \(\frac{(x - 30)}{20} - \frac{x}{30}\) = 2.5

⇒ x - 90 = 150

⇒ x = 240 km

A man leaves from P at 6 AM and reaches Q at 2 PM on the same day. Another man leaves Q at 8 AM and reaches P at 3 PM on the same day. At what time do they meet?

  1. 11 : 46 AM
  2. 11 : 24 AM
  3. 10 : 48 AM
  4. 11 : 00 AM

Answer (Detailed Solution Below)

Option 3 : 10 : 48 AM

Partial Speed Question 10 Detailed Solution

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Calculation:

Time taken by first man to cover journey = 2 PM – 6 AM = 8 hours

Time taken by another man to cover journey = 3 PM – 8 AM = 7 hours

Let total distance from P to Q be 56x km (LCM of 8 & 7)

⇒ Speed of first man = 7x km/hr

⇒ Speed of second man = 8x km/hr

⇒ Distance covered by first man in 2 hours = 14x km

⇒ Remaining distance = 56x – 14x = 42x km

⇒ Time taken to meet each other = 42x/ (7x + 8x) = 42/15 hrs

= 2 hrs 48 min

⇒ Time of meeting = 8:00 + 2:48 = 10:48 AM

Driving his car at the speed of 30 km/h Vinod reaches his office 5 min late. If his speed is 40 km/h, he reaches the office 3 min early. Find the distance he travels between his residence and his office.

  1. 16 km
  2. 18 km
  3. 20 km
  4. 15 km

Answer (Detailed Solution Below)

Option 1 : 16 km

Partial Speed Question 11 Detailed Solution

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Given:

Driving his car at the speed of 30 km/h Vinod reaches his office 5 min late and at speed of 40 km/h, he reaches the office 3 min early.

Concept used:

Time = Distance/Speed

Calculations:

Let the time be ‘t’ minutes  to reach office

Let the distance be D.

Time for 30km/h

⇒ (t + 5)/60 = D/30      ----(1)      (1 minute = 1/60 hours)

Time for 40 km/h

⇒ (t – 3)/60 = D/40      ----(2)

Subtract equation (2) from (1)

⇒ [t + 5 - (t - 3)]/60 = D/30 - D/40

⇒ (D/30) - (D/40) = 8/60

⇒ (4D - 3D)/120 = 8/60

⇒ D/120 = 8/60

⇒ D = 16 km

∴ The correct choice is option 1.

Shortcut Trick

Difference in time = Distance/Speed

⇒ [5 - (-3)]/60 = D/30 – D/40    (8 minutes = 8/60 in hours)

⇒ 8/60 = D/30 – D/40 

⇒ D/120 = 8/60

∴ D = 16 km

The speed of a train including stoppages is 75 kmph and excluding stoppages, the speed of the train is 90 kmph. For how many minutes does the train stop per hour? 

  1. 10 minutes
  2. 15 minutes
  3. 20 minutes
  4. 11 minutes

Answer (Detailed Solution Below)

Option 1 : 10 minutes

Partial Speed Question 12 Detailed Solution

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Given:

The speed of a train including stoppages is 75 kmph.

The speed of a train excluding stoppages is 90 kmph

Formula used:

Speed = distance/time

Calculation:

Since,

The speed of a train is 90 km/hour excluding stoppages

And the speed of the train is 75 km/hour including stoppages.

So, due to stoppage in 1 hour it covers = (90 – 75) km = 15 km less

∴ Time taken by train in stoppage = 15/90 = 1/6 hour = 10 minutes

Option 1 is the correct answer.

A car takes 50 minutes to cover a certain distance at a speed of 54 km/h. If the speed is increased by 25%, then how long will it take to cover three-fourth of the same distance?

  1. 40 minutes
  2. 30 minutes
  3. 35 minutes
  4. 25 minutes

Answer (Detailed Solution Below)

Option 2 : 30 minutes

Partial Speed Question 13 Detailed Solution

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Given:

A car takes 50 minutes to cover a certain distance at a speed of 54 km/h

Concept used:

Time = Distance/Speed

Calculation:

Distance cover in 50 minutes = 54 × 5/6 = 45 km

Now,

New speed = 54 × 5/4 = 67.5 km/h

3/4 of 45 = 33.75 km

Now,

Time taken = (33.75/67.5) × 60 = 1/2 × 60

⇒ 30 minutes

∴ It will take 30 to cover the distance.

Shortcut TrickSpeed is inversely proportional to the time

Speed ratio =   4 : 5

Time ratio   =   5 : 4

Now, 5 = 50 minutes

So, 4 = 40 minutes

So, 40 minutes is for the total journey.

Now, for 3/4th of the journey, it takes 40 × 3/4 = 30 minutes

∴ It will take 30 minutes.

A man is walking at a speed of 14 km/h. After every km, he takes rest for 7 minutes. How much time will he take to cover a distance of 7 km?  

  1. \(1\frac{1}{5}\) hours
  2. \(2\frac{1}{3}\) hours
  3. \(1\frac{1}{3}\) hours
  4. \(\frac{1}{5}\) hours

Answer (Detailed Solution Below)

Option 1 : \(1\frac{1}{5}\) hours

Partial Speed Question 14 Detailed Solution

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Given:

Speed of man = 14 km/h

Total distance to cover = 7 km

Formula used:

Time = distance/speed

Calculation:

If the man doesn't stop to rest, then

Time taken to complete the distance of 7 km = 7/14 = 1/2 h = 30 min

Total rest time = 7 × 6 = 42 min

Total time to cover the distance = 30 + 42 = 72 min = 1\(\frac{1}{5}\) hours

∴ The correct answer is 1\(\frac{1}{5}\) h.

Without any stoppage, Sunil travels a certain distance at an average speed of 80 km/hr. With stoppages, he covers the same distance at an average speed of 60 km/hr. How many minutes per hour does he stop for?

  1. 15 minutes
  2. 25 minutes
  3. 10 minutes
  4. 20 minutes

Answer (Detailed Solution Below)

Option 1 : 15 minutes

Partial Speed Question 15 Detailed Solution

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Given:

Speed without stoppage = 80 km/h

Speed with stoppage = 60 km/h

Formula used:

Speed = Distance/Time

Calculation:

Distance travel by Sunil with the speed of 80 km/h in one hour,

Distance = speed × Time

⇒ Distance = 80 × 1 = 80 km

Distance travel by Sunil with the speed of 60 km/h in one hour,

Distance = speed × Time

⇒ Distance = 60 × 1 = 60 km

Now, the time is taken to cover the extra 20 km with the speed of 80 km/h

Time = Distance/Speed

⇒ Time = 20/80

⇒ Time = 1/4 hour = (1/4) × 60

⇒ Time = 15 minutes

∴ Sunil stops on an average 15 minutes per hour.Shortcut Trick

Given:

Speed excluding stoppages = 80 km/h

Speed including stoppages = 60 km/h

Formula used:

Minutes of stops per hour = [(Faster speed - Slower speed)/Faster speed] × 60

calculation:

Minutes of stoppages per hour = [(80 - 60)/80] × 60

= (20/80) × 60

= 15 min

∴ Sunil stops on an average 15 minutes per hour.

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