Bodmas Rule MCQ Quiz - Objective Question with Answer for Bodmas Rule - Download Free PDF

Given:

395 × x = 2765

Calculation:

To isolate x, we need to divide both sides of the equation by 395:

x = 2765 / 395

x = 7

∴ The value of x is 7.

Given:

2⁰ × 1/2 × 2

Formula used:

Exponential and Multiplication rules

Calculation:

2⁰ × 1/2 × 2

⇒ 1 × 1

⇒ 1

∴ The correct answer is option (1).

Given:

10620 ÷ [(3/4) (72 + 66) - 20(3/4)] = ?

Formula Used:

Division of fractions: a ÷ (b/c) = a × (c/b)

Order of operations (BODMAS): Brackets → Orders (powers, roots) → Division → Multiplication → Addition → Subtraction

Calculation:

10620 ÷ [(3/4) (72 + 66) - 20(3/4)] = ?

⇒ 10620 ÷ [(3/4) (138) - 60/4)] = ?

⇒ 10620 ÷ [414/4 - 60/4] = ?

⇒ 10620 ÷ 354/4 = ?

⇒ 10620 × 4/354 = ?

⇒ 120

∴ Option 3 is the correct answer.

Given:

Expression: (44.7 + 347.33 + 3347.333 + 33347.333) ÷ 50 = ?

Calculation:

First, sum the numbers within the parentheses:

44.700

347.330

3347.333

33347.333

Sum = 37086.696

37086.696 ÷ 50 = 741.73392 ≈ 741.73

∴ The correct answer is option 4.

Calculation:

\(\frac {3}6 + \frac {4}6 + \frac {3}{12} +\frac {2}6 - 3 =\)

⇒ \(\frac {6}{12} + \frac {8}{12} + \frac {3}{12} +\frac {4}{12} - \frac{36}{12} =\)

⇒ \(\frac {6+8+3+4-36}{12}=\)

⇒ \(-\frac {15}{12}\)

∴ Option 4 is the correct answer.

Solution:

We have to follow the BODMAS rule

Calculation:

\(? = \sqrt[5]{{{{\left( {243} \right)}^2}}}\)

\(⇒ ? = (243)^{\frac{2}{5}}\)

\(⇒ ? = (3 × 3 × 3 × 3 × 3)^{2⁄5}\)

\(⇒ ? = (3^5)^{2⁄5}\)

⇒ ? = 3²

Concept used:

ax × ay = ax + y

ax ÷ ay = ax - y

Calculation:

(4 × 4)³ ÷ (512 ÷ 8)⁴ × (32 × 8)⁴ = (2 × 2)^{(? + 4)}

⇒ 4⁶ ÷ (64)⁴ × 256⁴ = (4)^{(? + 4)}

⇒ 4⁶ ÷ (4³)⁴ × (4⁴)⁴ = (4)^{(? + 4)}

⇒ 4^{(6 + 16 - 12)} = (4)^{(? + 4)}

⇒ 4¹⁰ = (4)^{(? + 4)}

So, ? + 4 = 10

⇒ ? = 10 - 4

Follow BODMAS (Brackets, Of, Division, Multiplication, Addition, Subtraction) rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved inside the bracket first,

Step-2-  Then any mathematical 'Of' or 'Exponent' must be solved,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

1251/3 × 271/3 × 1254/3 = 15 × 5?

⇒ 5 × 3 × 5⁴ = 15× 5^x

⇒ 15 × 5 ⁴ = 15× 5^x

⇒ x = 4

Hence option 4 is correct.

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

\(\frac{{7.2}}{{\sqrt[3]{{0.729}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

\(\Rightarrow \frac{{7.2}}{{\sqrt[3]{{\frac{{729}}{{1000}}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

\(\Rightarrow \frac{{7.2}}{{\sqrt[3]{{{{\left( {\frac{9}{{10}}} \right)}^3}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

\(\Rightarrow {\rm{\;}}\frac{{7.2}}{{\sqrt[3]{{{{\left( {0.9} \right)}^3}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

\(\Rightarrow \frac{{7.2}}{{0.9}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

⇒ 8 = (?)³/(2)³

⇒ (2)³ = (?)³/(2)³

⇒ 2³ × 2³ = (?)³

⇒ 4³ = (?)³

⇒ ? = 4

Shortcut Trick Formula:

(a+b)2 - 4ab = (a-b)2

Calculation:

(957 + 932)2 - 4 × 957 × 932

= (957 - 932)2

= 252 = 625

Alternate Method GIVEN:

\(( 957 + 932 )^2\) - 4 × 957 × 932.

FORMULA USED:

BODMAS 

CALCULATION :

⇒ \((1889)^2\) - 4 × 957 × 932 

⇒ 3568321 - 4 × 957 × 932 

⇒ 3568321 - 3567696  =  625 

∴ The value is 625.

Concept used:

Calculation:

196² × 56 ÷ 14⁵ × 1021 

⇒ (14²)² × (56/14⁵) × 1021 

⇒ [14⁴ × (56/145)] × 1021 

⇒ (56/14) × 1021 

⇒ 4 × 1021 = 4084

∴ The answer will be 4084.

Using BODMAS rule:

⇒ 63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + (- 2)(- 1)}]

⇒ 63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + 2}]

⇒ 63 - (42) ÷ 21

1132.757 – 2315.996 – 1753.829 + 2 × 2846.639

= 1133 – 2316 – 1754 + 5694

= (1133 + 5694) – (2316 + 1754 )

= 6827 – 4070

= 2757

Concept used:

Calculation:

\(56 \div \left[\frac{1}{3}\left\{ {15 + 12 - \left( {9 + 6 - \overline {5 + 7} } \right)} \right\} \right] \)

⇒ 56 ÷ [(1/3){15 + 12 - (9 + 6 - 12)}]

⇒ 56 ÷ [(1/3){15 + 12 - (15 - 12)}]

⇒ 56 ÷ [(1/3){15 + 12 - 3}]

⇒ 56 ÷ [(1/3){27 - 3}]

⇒ 56 ÷ [(1/3)(24)]

⇒ 56 ÷ 8

⇒ 7 

∴ ? = 7

Important Points

If in any simplification problem there is (  ̅  ) bar sign above any operation then we should perform the operation at the beginning, whatever the operation is. Then we will follow the chart given above.