Average velocity and average speed MCQ Quiz - Objective Question with Answer for Average velocity and average speed - Download Free PDF
Last updated on Apr 14, 2025
Latest Average velocity and average speed MCQ Objective Questions
Average velocity and average speed Question 1:
Give below are two statements
Statement I : Area under velocity- time graph gives the distance traveled by the body in a given time.
Statement II : Area under acceleration- time graph is equal to the change in velocity- in the given time.
In the light of given statement, choose the correct answer from the options given below
Answer (Detailed Solution Below)
Average velocity and average speed Question 1 Detailed Solution
The Correct answer is Statement I is incorrect but Statement II is true.
Key Points
Statement I : Area under velocity- time graph gives the distance traveled by the body in a given time.\(\overrightarrow{\mathrm{S}}=\int \overrightarrow{\mathrm{V}} d t\)
Therefore area under the velocity time graph gives displacement.
Hence statement I is false.
Statement II : Area under acceleration- time graph is equal to the change in velocity- in the given time.
a = \(\frac{d V}{d t}\)
⇒ dV = adt
⇒ \(\int d \mathrm{~V}=\int a d t\)
Hence statement - II is correct.
Average velocity and average speed Question 2:
A car covers the first half of a certain distance with a speed v1 and the second half with a speed v2. The average speed (v) of v1 and v2 during the whole journey will be
Answer (Detailed Solution Below)
Average velocity and average speed Question 2 Detailed Solution
Concept:
- Distance travelled is the product of speed and the time taken while travelling with that speed.
\( speed = \frac{distance}{time}\)
- The average speed is defined as the total distance travelled by the total time taken during the process.
\(Average \ speed = \frac{total \ distance}{total \ time}\)
Calculation:
Let the distance from X to Y is d
So, the distance travelled from X to Y or Y to X is d.
Total distance hence travelled is d + d = 2d
Speed of Car moving from X to Y is V1
distance from moving X to Y is d
time taken
\(t_1 = \frac{d}{v_1}\) ----(1)
Similarly, time taken from moving Y to X is
\(t_2 = \frac{d}{v_2}\) ----(2)
total time taken t
\(t = t_1 + t_2 = \frac{d}{v_1} + \frac{d}{v_2}\)
Average speed is the total distance by the total time
\(s= \frac{2d}{ \frac{d}{v_1} + \frac{d}{v_2}}\)
\(\implies s= \frac{2d}{d \ \left ( \frac{1}{v_1} + \frac{1}{v_2} \right )}\)
\(\implies s= \frac{2V_1 V_2}{V_1 + V_2}\)
Clearly, the average speed is the harmonic mean.
Additional Information
If H is the Harmonic mean of numbers a and b and is given by
\({\rm{H}} = \frac{{2{\rm{ab}}}}{{{\rm{a}} + {\rm{b}}}}\)
Arithmetic mean = Sum of terms/Number of terms
Geometric mean = G.M. = \(\rm\sqrt{ab}\)
Average velocity and average speed Question 3:
A person travels in a car from p to q with uniform speed u and returns to p with uniform speed v. The average speed for his round trip is
Answer (Detailed Solution Below)
Average velocity and average speed Question 3 Detailed Solution
Concept Used:
The average speed for a round trip, where the speeds are different for the two parts of the journey, is calculated using the formula:
Average speed = (2 × u × v) / (u + v)
Calculation:
We have:
⇒ Average speed = (2 × u × v) / (u + v)
∴ The correct answer is: (2 × u × v) / (u + v)
Average velocity and average speed Question 4:
The average speed of a car during the Journey on a straight highway for 2 hr was 35 km/hr. Which among the following statement/statements are surely correct.
A. The total distance traveled by him is 70 km.
B. He must have travelled 35 km in the first hour.
C. His speed may change during the journey.
D. He will travel 105 km if he continues with this average speed for another hour.
Answer (Detailed Solution Below)
Average velocity and average speed Question 4 Detailed Solution
Concept:
Average speed:
- The total distance travelled divided by the total time taken is called average speed.
\(Average \ speed = \frac{total \ distance}{total \ time}\) ----(1)
- The average speed is for the whole Journey.
- The speed at any instant may change.
- If the average speed is 35 km/hr for two hours, that not necessarily means 35 km is travelled in one hour.
- It is possible the speed might have been higher or lower than the 35 km/hr. But, it is the ratio of total distance by total time.
Calculation:
From equation (1).
total distance = Average speed × total time.
If speed = 35 km / hr and time is 2 hr, distance = 35 km/hr × 2 hr = 70 km.
f time is 3 hr, distance = 35 km/hr × 3 hr = 105 km / hr
So, for first three-hour distance is 105 km and 2 hours it is 70 km.
Conclusion:
- By calculation, A and D is correct.
- Statement B says he must have travelled 35 km in first hour is not correct. In first hour the speed may have been different from the average speed of 2 hours. So, it is not correct.
- Statement C is correct. His speed may change during the journey as average speed is for a certain distance not at any instant,
So, A, C, D are correct statements.
Average velocity and average speed Question 5:
Observe the given distance-time graph.
Identify the respective speeds of the body when it moves from O to A and B to C.
Answer (Detailed Solution Below)
Average velocity and average speed Question 5 Detailed Solution
CONCEPT:
- Velocity: The rate of change of position i.e. rate of displacement with time is called velocity.
\(v = \frac{{{x_2} - {x_1}}}{{{t_2} - {t_1}}} = \frac{{{\rm{\Delta }}x}}{{{\rm{\Delta }}t}}=\tan{\theta}\)
Where x2 = displacement of the object at t2 and x1 = displacement of the object at t1
- It is a vector quantity having the symbol v.
- A slope of a tangent on the position-time graph represents the velocity of the particle.
EXPLANATION:
- The speeds of the body when it moves from O to A is
\(\Rightarrow V_{OA}=\frac{AD}{OD}=\frac{2}{1}=2\,m/s\)
- The speeds of the body when it moves from B to C is
\(\Rightarrow V_{BC}=\frac{CG}{BG}=\frac{2}{0.5}=4\,m/s\)
Top Average velocity and average speed MCQ Objective Questions
An object travels 16 m in 4 s and then another 16 m in 2 s. What is the average speed of the object?
Answer (Detailed Solution Below)
Average velocity and average speed Question 6 Detailed Solution
Download Solution PDFCONCEPT:
- Average speed: The total path length travelled divided by the total time interval during which the motion has taken place is called the average speed of the particle.
Total distance travelled by the object = 16 m + 16 m = 32 m
Total time taken = 4 s + 2 s = 6 s
\(Average\;speed\;\left( {\bar v} \right) = \frac{{total\;path\;length\;\left( S \right)}}{{total\;time\;taken\;\left( t \right)}}=\frac{32}{6}=5.33\, m/s\)
- Therefore, the average speed of the object is 5.33 m/s.
A train crossed a 120 m long platform in 12 seconds and 165 m long platform in 15 seconds. The speed of the train was:
Answer (Detailed Solution Below)
Average velocity and average speed Question 7 Detailed Solution
Download Solution PDFFormula Used:
Distance = Speed × Time
Calculations:
Let the speed of the train be ‘x’ m/s and the length of the train be ‘y’ m
A train crossed a 120 m long platform in 12 seconds,
⇒ 12 × (x) = 120 + y ----(1)
A train crossed a 165 m long platform in 15 seconds,
⇒ 15 × (x) = 165 + y ----(2)
Equation (2) - Equation (1) we get,
⇒ 3x = 45
⇒ x = 15 m/s = 15 × (18/5) km/h = 54 km/h
∴ The speed of the train is 54 km/h.If a particle travels a distance ‘s’ in time t1 to t2, the average speed Vav is ______.
Answer (Detailed Solution Below)
Average velocity and average speed Question 8 Detailed Solution
Download Solution PDFConcept:
- Distance travelled is the product of speed and the time taken while travelling with that speed.
\( speed = \frac{distance}{time}\)
- The average speed is defined as the total distance travelled by the total time taken during the process.
\(Average \ speed = \frac{total \ distance}{total \ time}\)
Calculation:
Given, the distance travelled is s
time interval t = t2 - t1
Average speed Vav
\(Average \ speed = \frac{total \ distance}{total \ time}\)
So
\(V_{av} = \frac{s}{t_2 - t_1}\)
The correct option is
\(\frac{s}{t_2 - t_1}\)
An object starts from rest at x = 0 m and moves with a constant acceleration of 1.6 m/s2 along the x-axis. During its journey from x = 12.8 m to x = 20.0 m, its average velocity will be __________.
Answer (Detailed Solution Below)
Average velocity and average speed Question 9 Detailed Solution
Download Solution PDFConcept:
Equation of motion:
- Equations of motion of kinematics describe the basic concept of the motion of an object such as the position, velocity, or acceleration of an object at various times.
- These three equations of motion govern the motion of an object in 1D, 2D, and 3D.
- Three equations: v = u + at, s = ut + 0.5 at2, 2as = v2 - u2
- Here, u = initial velocity, v = final velocity, s = displacement, t = time
- Under the influence of gravity, acceleration a is replaced by acceleration due to gravity g.
Calculation:
Given,
Initial velocity, u = 0 m/s, Acceleration, a = 1.6 m/s2
From the second equation of motion,
s = ut +0.5 at2
12.8 = 0.8 t12
\(t_1^2=\frac{12.8}{0.8}=16\)
t1 = 4 sec.
For s = 20
20 = 0 × t2 + 0.5 × 1.6 t22
t2 = 5 sec.
The average velocity can be calculated as,
\(v_{avg}=\frac{total\, \, displacement}{total\, \, time\, duration}\)
\(v_{avg}=\frac{20 - 12.8}{5 - 4}=7.2m/s\)
Hence, What is its average velocity 7.2m/s.
The initial odometer reading of a car is 369 km. It travelled for 2 hours and the final odometer reading showed 469 km. Find the approximate average speed of the cab.
Answer (Detailed Solution Below)
Average velocity and average speed Question 10 Detailed Solution
Download Solution PDFCONCEPT:
- Average speed: The total path length travelled divided by the total time interval during which the motion has taken place is called the average speed of the particle.
\(Average\;speed\;\left( {\bar v} \right) = \frac{{total\;path\;length\;\left( S \right)}}{{total\;time\;taken\;\left( t \right)}}\)
EXPLANATION:
Given - Initial odometer reading (s1) = 369 km, final odometer reading (s2) = 469 km, and Time (t) = 2 hour
- Mathematically Average speed is written as
\(\Rightarrow v = \frac{\Delta s}{t}=\frac{469-369}{2}=50\,km/hr\)
- To convert the km/hr to m/s, multiply km/hr by 5/18, therefore
\(\Rightarrow v = 50\times \frac{5}{18}\approx14\, m/s\)
NOTE:
- Odometer or odograph: It is a device used to measure the distance travelled by the vehicle.
- Speedometer or speed meter: A device used by the vehicle to measure the speed of the vehicle.
A person runs on a 300m circular track and comes back to the starting point in 200s. Calculate the average speed and average velocity.
Answer (Detailed Solution Below)
Average velocity and average speed Question 11 Detailed Solution
Download Solution PDFCONCEPT:
- Average velocity: The average velocity of an object is defined as the displacement per unit of time.
- Let x1 and x2 be its positions at instants t1 and t2 respectively.
- Then mathematically we can express average velocity (v) as:
\(\Rightarrow v = \frac{displacement}{Time taken}\)
\(\Rightarrow v= \frac{x_{2} - x_{1}}{t_{2} - t_{1}}= \frac{Δ x}{Δ t}\)
where x2 - x1, signifies a change in position (denoted by Δx) and t2 - t1 is the corresponding change in time (denoted by Δt).
- Average velocity can be represented as Vav also.
- The average speed of an object is obtained by dividing the total distance travelled by the total time taken:
\(\Rightarrow Average \; speed = \frac{Total \; distance \; travelled}{total\; time \; taken}\)
- If the motion is in the same direction along a straight line, the average speed is the same as the magnitude of the average velocity.
CALCULATION:
Given that:
The total length of the track = 300m.
Time is taken to cover this length = 200s
\(\Rightarrow Average \; speed= \frac{Total \; distance \; travelled}{total\; time \; taken}\)
\(\Rightarrow Average \; speed= \frac{300}{200} ms^{-1} = 1.5 ms^{-1}\)
- As the person comes back to the same point, the net displacement is zero. Therefore, the average velocity is also zero.
- option 1 is the correct answer.
Mahesh travels from his house to the chemical plant office in 10 minutes and returns home in 15 minutes without going anywhere. Find the average velocity of Mahesh if the distance between his house and the chemical plant office is 3 km.
Answer (Detailed Solution Below)
Average velocity and average speed Question 12 Detailed Solution
Download Solution PDFCONCEPT:
- Distance (S): The total distance traveled by an object from a starting point is called path length. Thus the total path length of an object is called distance traveled by that object.
- Displacement (S’): The minimum path length between the starting point to the final point is called displacement.
- Average speed: The total path length traveled divided by the total time interval during which the motion has taken place is called the average speed of the particle.
\(Average\;speed\;\left( {\bar v} \right) = \frac{{total\;path\;length\;\left( S \right)}}{{total\;time\;taken\;\left( t \right)}}\)
- Average velocity: The ratio of net displacement to total time taken is called average velocity.
\(Average\;velocity\;\left( {\bar V} \right) = \frac{{{\rm{Net\;displacement\;}}\left( {{\rm{S'}}} \right)}}{{time\;taken\;\left( t \right)}}\)
CALCULATION:
- As Mahesh goes to the office and returns back to his house, so the initial point and final point is same for him.
So net displacement of Mahesh (S) = 0
Total time taken (t) = 10 + 15 = 25 min
Average velocity = (Net displacement)/(total time taken) = 0/25 = 0
Hence option 4 is correct.
The velocity-time graph for a car moving in a straight line is shown below, the total distance covered by the body is:
Answer (Detailed Solution Below)
Average velocity and average speed Question 13 Detailed Solution
Download Solution PDFConcept:
- Displacement (x): The change in the position of an object is called displacement.
- Displacement is a one-dimensional quantity representing the smallest separation between two defined points.
- The standard unit of displacement in the International System of Units (SI) is the meter (m).
- Velocity (V): The rate of change of displacement is called velocity. It is a vector quantity.
- The SI unit of velocity is called m/s and the CGS unit is cm/s.
- The slope of the displacement-time graph gives the velocity
\(Instanteneous\;Velocity\;\left( v \right) = \frac{{dx}}{{dt}}\)
Hence, dx = v⋅dt
\(Displacement\;\left( X \right) = \mathop \smallint \nolimits_{{x_1}}^{{x_2}} dx = \mathop \smallint \nolimits_{{t_1}}^{{t_2}} V \cdot dt\)
- Thus the area under the velocity-time graph gives the displacement. Similarly, the area under-speed time graph gives the total distance travelled
Calculation:
Area under the velocity-time curve represents displacement.
To get exact position at t, we need to calculate the area of the shaded part in the curve as shown below
Area of trapezium = ½ × (Sum of parallel sides) × distance between them.
⇒ Area of trapezium = ½ × (15 + 5) × 100
⇒ Area of trapezium = ½ × 20 × 100 = 1000 m
Hence the correct option is 1000 meter.
A car that can travel at a maximum speed of 120 km/hr takes 7 hours 45 minutes to cover a distance of 372 km. What is the difference between the maximum and the average speed of this car?
Answer (Detailed Solution Below)
Average velocity and average speed Question 14 Detailed Solution
Download Solution PDFConcept:
- Speed: The distance traveled by the body in unit time.
\(Speed = \frac{{Distance}}{{Time}}\)
Also, \(Time= \frac{{Distance}}{{Speed}}\)
Average speed:
- The total path length traveled divided by the total time interval during which the motion has taken place is called the average speed of the particle.
\(\left( {\bar v} \right) = \frac{{total\;path\;length\;\left( S \right)}}{{total\;time\;taken\;\left( t \right)}}\)
Calculation:
Vmax = 120 km/hr
Distance = 372 km
Time (t) = 7 hr 45 min
= 7+ (45/60) = (31/4) Hr
\(Average\;Speed = \frac{{Total\;Distance}}{{Total\;Time}}\) = \( \frac{{372\times4}}{{31}}\)
Vavg = 48 (km/hr)
Hence the required difference is = 120 - 48 = 72 km/hr
In the following table, the readings of an odometer at different times of a journey are given:
Time (AM) |
Odometer reading (km) |
8.00 |
6640 |
8.30 |
6658 |
9.00 |
6676 |
9.30 |
6694 |
10.00 |
6712 |
The speed of the vehicle in metres per second is
Answer (Detailed Solution Below)
Average velocity and average speed Question 15 Detailed Solution
Download Solution PDFConcept:
- Speed: Total distance traveled by the total time taken is called speed.
- Speed measures how fast the body is moving.
\(\rm speed = \dfrac{distance}{time}\)
- Average speed: It is defined as the total distance traveled by the total time taken.
- Odometer: It is the device that is used to measure the distance traveled by a vehicle.
- Average speed: The total distance traveled by the total time taken will give the average speed.
\(\rm Average \ speed = \dfrac{total \ distance}{total \ time}\)
- Conversion of speed from km / hr to m /s
1 km = 1000 m
1 hr = 3600 second
So,1 km / 1 hr = 1000 m / 3600 second = \(\frac{5}{18} \ m / s\)
Calculation:
The initial reading of the odometer = 6640 km (at 8.00)
Final reading of the odometer = 6712 km (at 10.00)
Distance travelled d = 6712 km - 6640 km = 72 km
Time taken = 10;00 - 8:00 = 2 hr
So, average speed = (total distance) / (total time) = 72 km / 2 hr = 36 km / hr
Now, this has to be converted into m /s by multiplying it with \(\frac{5}{18} \ m / s\)
So,
\(36 \ km /hr = 36 \times \frac{5}{18} m /s = 10\ m /s\)
So, the correct option is 10 m / s.
Mistake Points
Students may write answer in km/hr instead of m /s . Questions should be always read properly.