Overview
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Pascal’s Triangle is a special triangle made by arranging numbers in a pattern. It is named after the French mathematician Blaise Pascal. In this triangle, each number is the sum of the two numbers just above it from the previous row. The triangle starts with 1 at the top, and every row starts and ends with 1.
Pascal’s Triangle is very useful in math. It helps in solving problems in probability, algebra, and combinatorics (which is the study of counting). For example, it can be used to find the coefficients in binomial expansions (like when you expand (a+b)n. It’s also used to calculate the number of ways certain events can happen, like getting heads and tails when tossing coins.
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Pascal’s Triangle is a triangle-shaped pattern made up of numbers. Each row starts and ends with the number 1. The numbers in between are found by adding the two numbers directly above them from the row above. This pattern continues row by row.
Pascal’s Triangle is very useful in math, especially in probability, algebra, and combinatorics (which is the study of counting and arrangements). It helps us find the chances of certain outcomes—like in a coin toss—and is also used to get the coefficients when expanding expressions like (x+y)n.
For example, the third row of Pascal’s Triangle is 1, 2, 1, and these numbers are the coefficients in the expansion of (x + y)² = x² + 2xy + y².
Pascal’s triangle contains several patterns, some examples of Pascal triangle patterns are:
The following patterns are followed in Pascal’s triangle:
Each number is the sum of the numbers directly above it.
The first diagonal is made up of 1’s.
The second diagonal is made up of counting numbers, such as 1,2,3,4,…
The third diagonal contains triangular numbers such as 1, 3, 6, 10, 15, etc.
The fourth diagonal contains tetrahedral numbers such as 1,4,10,20, and so on.
Symmetrical
The triangle is symmetrical as well. Like a mirror image, the numbers on the left side have identical matching numbers on the right side.
Horizontal sums
Using the Pascal’s triangle formula to calculate the sum of the elements in the Pascal’s triangle’s \( n^{th} \)row. They always double (powers of 2).
Square
The third diagonal contains square numbers. A square number is the sum of any two consecutive numbers in the triangle’s third row. When all of the circled numbers in the image are added up, they form a square number.
For example: \( 4^{2 }= 6+10 = 16 \)
Fibonacci sequence
The Fibonacci numbers can be calculated by adding the elements of the Pascal’s triangle’s rising diagonal lines.
The Pascal’s triangle formula is:
\( \binom{n+1}{r} = \binom{n}{r-1}+\binom{n}{r} \)
Combinations are represented by this parenthetical notation, so another way to express \( \binom{n}{r} \) would be \( _{n}C_{r} = \frac{n!}{r!\left ( n-r \right )!} \)
To make the triangle, begin with a “1” at the top and continue with two 1’s on the next row, forming a triangle. Begin and end each subsequent row with a 1 and compute each interior term by adding the two numbers above it.
We will get a Pascal triangle if we repeat this process. This is an endless triangle.
Pascal’s Triangle Properties are
Pascal’s triangle can also be used to calculate the coefficients of terms in a binomial expansion. Pascal’s triangle is a useful tool for quickly determining whether or not the binomial expansion of a given polynomial is correct.
The coefficients in binomial expansions are defined by Pascal’s triangle. That is, the coefficients of the polynomial’s expanded expression are represented in the nth row of Pascal’s triangle \( \left ( x+y \right )^{n} \)
For example:
Expand this \(\left ( 2+3x \right )^{3}\)
Solution:
when comparing with the binomial formula then,
x = 2, b = 3x and n = 3
\(\Rightarrow \left ( 2+3x \right )^{3}= 2^{3}+\left ( _{1}^{3} \right )2^{2}\left ( 3x \right )^{1} + \left ( _{2}^{3} \right )2 \left ( 3x \right )^{2} + \left ( 3x \right )^{3} \)
\( = 8+36x + 54x^{2}+27x^{3} \)
Expansion of \( \left ( x+y \right )^{n} \) is \left ( x+y \right )^{n} = a_{0}x^{n} + a_{1}x^{n-1}y + a_{2}x^{n-2}y^{2} + ..+ a_{n-1}xy^{n-1} + a_{n} y^{n} , where the coefficients of the form \( a_{k} \) are the nth row of Pascal’s triangle. This can be stated as follows: \( a_{k} = \binom{n}{k} \)
Pascal’s Triangle is a helpful tool in math and is used in many different ways. Here are some of its main uses:
Pascal’s triangle is used extensively in mathematics and statistics. The binomial expansion can be found using Pascal’s triangle. Pascal’s triangle is also used in probabilistic applications and combination calculations.
We will look at the two coin toss examples here. In probability, Pascal’s triangle can be used to simplify counting the probabilities of an event. Pascal’s triangle, for example, can show us how many different ways we can combine heads and tails in a coin toss.
Example of Toss Two coins
Coin flip |
Possible sequences of heads (H) or tails (T) |
Pascal’s triangle |
2 |
HH HT TH TT |
1,2,1 |
There are 2\times 2= 4 possible heads/tails sequences after three coin flips.
When the sequences are sorted into groups of “how many heads (2, 1, or 0),” each group contains 1, 2, 1, and 1 sequences, respectively.
Example of Toss Three coins
Coin flip |
Possible sequences of heads (H) or tails (T) |
Pascal’s triangle |
3 |
HHH HHT HTH THH HTT THT TTH TTT |
1 3 3 1 |
There are 2\times 2\times 2 = 8 possible heads/tails sequences after three coin flips.
When the sequences are sorted into groups of “how many heads (3, 2, 1, or 0),” each group contains 1, 3, 3, and 1 sequences, respectively.
Example 1: Find the sum of the numbers in the 5th row of Pascal’s Triangle.
Solution:
We use the formula:
Sum = 2ⁿ, where n is the row number.
Here, n = 5, so:
Sum = 2⁵ = 32
Answer: The sum of the numbers in the 5th row of Pascal’s Triangle is 32.
Example 2:With four coin tosses, what is the probability of obtaining exactly two heads?
Solution:
There are
1+4+6+4+1 = 16
\( 2^{4} =16 \)
There are 16 possible outcomes, and 6 of them produce exactly two heads.
As a result, the probability is
\( \frac{6}{16} = 37.5% \)
Example 3: A coin is tossed 4 times. What is the probability of getting exactly 3 heads?
Solution:
When a coin is tossed 4 times, the total number of possible outcomes is:
2⁴ = 16
Now, we look at how many of these outcomes give us exactly 3 heads.
From Pascal’s Triangle, the number of ways to get exactly 3 heads out of 4 tosses is 4.
So, the probability = 4/16 = 1/4 = 25%
Answer: The probability of getting exactly 3 heads is 25%.
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