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Antisymmetric Relation is a relation R of a set A is antisymmetric if (a,b) ∈ R and (b,a) ∈ R, then a=b. Relations defined between sets and their types are an essential aspect of set theory. Sets indicate the collection of ordered elements, while relations and functions are there to denote the operations performed on elements in the sets. A relation between two sets A and B is a collection of ordered pairs of elements from A and B that satisfy the relation condition. It is a subset of the cartesian product AXB, of the sets A and B
There are different types of relations that can connect elements in two sets or within the same set.
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An antisymmetric relation is a type of relation in mathematics that follows a special rule.
Let’s say we have a set A, and a relation R is defined on it. The relation R is antisymmetric if the following condition is true:
If a is related to b and b is related to a, then a must be equal to b.
In symbols, this means:
If (a, b) is in R and (b, a) is also in R, then a = b
Where a and b are elements from the set A.
Example of Antisymmetric Relation: If we have a set R, where ‘a is less than equal to b’ where both a and b belong to R, then we see that for any a is less than equal to b as well as for the reverse to be true we must have a=b. Suppose a=4, b=5, then ‘a is less than equal to b’ is satisfied but ‘b less than equal to a’ is not satisfied. Thus this relation is an Antisymmetric Relation.
If we are given a set A and a relation on this set A, then the condition that must be satisfied for becoming an antisymmetric relation is given below:
\( aRb\ \&\ bRa\Rightarrow a=b \), where \( a,\ b\in A \)
We can also write the condition as,
\( \left(a,\ b\right)\in R\ \&\ \left(b,\ a\right)\in R\Rightarrow a=b,\ \forall\ a,\ b\in A \)
OR
\( \left(a,\ b\right)\in R\ \&\ a\ne b\Rightarrow\left(b,\ a\right)\notin R,\ \forall\ a,\ b\in A \)
R will not be antisymmetric if \( \left(a,\ b\right)\in R\ \&\ \left(b,\ a\right)\in R\ \) but\( a\ne b \), for any \( a,\ b\in A \)
Let us understand the characteristics of antisymmetric relations through a digraph. The relations between the elements of two sets or the same set can be represented with the help of digraphs that use vertices to represent elements and directional edges between vertices to represent a relation between elements. Consider the following digraph of some relation R defined on the elements of a set.
We have ordered pairs such as \( R=\left\{\left(a,\ c\right),\left(a,\ b\right),\left(c,\ b\right)\right\} \). We can say that \( \left(a,\ b\right)\in R\ \&\ a\ne b\Rightarrow\left(b,\ a\right)\notin R,\ \forall\ a,\ b\in A \). Thus this is an Antisymmetric Relation.
Here from the above digraph, we get the relation set as \( R=\left\{\left(a,\ a\right),\left(b,\ b\right),\left(c,\ c\right),\left(d,\ d\right),\left(a,\ d\right),\left(a,\ b\right),\left(c,\ a\right),\left(c,\ b\right),\left(b,\ d\right)\right\} \) for the mother set of \( A=\left\{a,\ b,\ c,\ d\right\} \)
We see that for this relation set satisfies both the condition of antisymmetry, such as the first condition,
\( \left(a,\ b\right)\in R\ \&\ \left(b,\ a\right)\in R\Rightarrow a=b,\ \forall\ a,\ b\in A \).
This condition is satisfied by the ordered pairs \( \left(a,\ a\right),\left(b,\ b\right),\left(c,\ c\right),\left(d,\ d\right) \), and also the second condition is satisfied such as,
\( \left(a.\ b\right)\in R\ \&\ a\ne b\Rightarrow\left(b,\ a\right)\notin R,\ \forall\ a,\ b\in A \)
This condition is satisfied by the ordered pairs \( \left(a,\ d\right),\left(b,\ d\right),\left(c,\ b\right),\left(c,\ a\right),\left(a,\ b\right) \)
Thus the above-given digraph is an Antisymmetric relation.
Now this above-given digraph is not an Antisymmetric relation.
For the mother set \( A=\left\{1,\ 2,\ 3,\ 4\right\} \), we get the relation set as \( R=\left\{\left(2,\ 2\right),\left(3,\ 3\right),\left(1,\ 4\right),\left(4,\ 1\right),\left(1,\ 3\right),\left(3,\ 1\right),\left(2,\ 1\right),\left(2,\ 3\right),\left(4,\ 3\right)\right\} \)
This relation satisfies neither of the conditions of the Antisymmetric matrix.
Here \( \left(a,\ b\right)\in R\ \&\ \left(b,\ a\right)\in R\ but\ a\ne b\ \), as have only (2, 2) and (3, 3), and not (1, 1) and (4, 4).
Also, we have (1, 4) and (4, 1) but \( 1\ne4 \), so the above digraph is an Antisymmetric relation.
Basically, we can conclude that if we are given a digraph where we have a bidirectional arrow between two different elements then it can be said that it is not an Antisymmetric relation. As in the above digraph, we have a bidirectional arrow between 1 and 3 as well as between 1 and 4, so we can directly say it is not an Antisymmetric relation.
Let us consider a relation ‘is divisible by’ on an ordered pair relation on a set of all integers. We can find an ordered pair (x,y) in relation ‘R’ and here, ‘x’ and ‘y’ are whole numbers or integers. Also, x is divisible by y.
The properties of an antisymmetric relation say:
By antisymmetric relation, we can say that if we have two sets, and one element of the first set is related to one element of the other set by some relation. Then, the element of the second set is related to the same element of the first set, following the same relation. Also, this can only be true when both the elements from the two different sets are equal.
Example of Antisymmetric Relation: Consider a set A = {1, 2, 3, 4} and let R be a relation on set A. Let us now find the antisymmetric relation on A.
Let (1,1), (2,2), (3,3), (4,4) be the ordered pairs in the relation R on set A.
As we can see that there are no pairs of distinct elements, so, the relation R on set A is antisymmetric.
To find out whether a relation is antisymmetric, you can follow these easy steps:
Symmetric Relation |
Asymmetric Relation |
Antisymmetric Relation |
Any relation R on a set A is said to be symmetric if (a,b)\(\in \)R then (b,a)\(\in \)R. |
Any relation R on a set A is said to be asymmetric if (a,b)\(\in \)R but (b,a)\(\notin\)R. |
Any relation R on a set A is said to be antisymmetric if (a,b)\(\in \)R and (b,a)\(\in\)R, then a = b. |
“Is equal to” is a symmetric relation. For example: 7 = 5 + 2, 5 + 2 = 7. |
“Is less than” is an asymmetric relation. For example: 7 is less than 12, but 12 is not less than 7. |
If \(a\ne\), then (b,a)\(\in\)R. |
The difference between Symmetric Relation and Antisymmetric Relation is given below.
Symmetric Relation |
Antisymmetric Relation |
\( \left(a,\ b\right)\in R\Rightarrow\left(b,\ a\right)\in R \) |
\( \left(a,\ b\right)\in R\ and\ \left(b,\ a\right)\in R\Rightarrow a=b \) |
A symmetric relation is bidirectional i.e if aRb then bRa |
An antisymmetric relation is unidirectional, i.e., if aRb then we do not have bRa unless a=b |
Every vertex of the digraph for a symmetric relation has directed edges from and to other vertices. |
Every vertex in the digraph of an antisymmetric relation has directed edges either from or to other vertices. |
Example 1: Check whether the given relationship is Antisymmetric or not.
\( R=\left\{\left(a,\ a\right),\left(b,\ b\right),\left(c,\ c\right)\right\}\ on\ X=\left\{a,\ b,\ c\right\} \)
Solution: In the given relation R we see that all the ordered pairs have dissimilar elements. Therefore R satisfies the following condition, \( \left(a,\ b\right)\in R\ and\ \left(b,\ a\right)\in R \),
Thus we can say that a=b and hence the given relation is an Antisymmetric Relation.
Example 2: If \( S=\left\{1,\ 2,\ 3,\ 4,\ 5\right\} \), then find the Antisymmetric Relation for set S.
Solution: We have to find such a relation that satisfies the following condition for becoming Antisymmetric.
\( \left(a,\ b\right)\in R\ and\ \left(b,\ a\right)\in R\Rightarrow a=b \)
With this condition we get,
\( R=\left\{\left(1,\ 1\right),\left(2,\ 2\right),\left(3,\ 3\right),\left(4,\ 4\right)\right\} \)
Thus R is the resultant Antisymmetric Relation.
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