Overview
Test Series
Titration of oxalic acid with potassium permanganate is a classic example of redox titration, where a reduction and oxidation reaction takes place between two chemical substances. In this experiment, potassium permanganate (KMnO4) acts as a strong oxidizing agent, while oxalic acid (H2C2O4) serves as the reducing agent. The main goal of this titration is to determine the concentration or strength of the potassium permanganate solution using a known concentration or strength of oxalic acid. This reaction is commonly performed in chemistry labs to understand redox behaviour and practice accurate measurement skills.
In this titration, a redox reaction takes place where electrons are transferred between oxalic acid and potassium permanganate.Potassium permanganate (KMO4) gets reduced from Mn7+ to Mn2+, while oxalic acid gets oxidised to carbon dioxide (Co2). This reaction only happens in an acidic medium, and that’s where sulfuric acid (H2SO4) comes in- it provides the necessary acidic environment for the reaction to proceed smoothly. The overall equation for the reaction is:
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2 \mathrm{KMnO}_4+5 \mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4+3 \mathrm{H}_2 \mathrm{SO}_4 \rightarrow 2 \mathrm{MnSO}_4+10 \mathrm{CO}_2+\mathrm{K}_2 \mathrm{SO}_4+8 \mathrm{H}_2 \mathrm{O}
This reaction is temperature-sensitive and needs to be carried out in warm conditions to ensure the oxalic acid reacts properly with KMnO4.
For the titration of oxalic acid with potassium permanganate, you will need the following chemical and apparatus:
(a) Preparation of 0.1M standard solution of oxalic acid:
To begin the experiment, we will first calculate the amount required for 0.1 M of oxalic acid. The molecular mass of oxalic acid is 126 g. To prepare a M/10 oxalic acid solution, we need to dissolve 12.6 g of oxalic acid per litre of solution. Alternatively, we can dissolve 3.15 g of oxalic acid crystals in water and make the solution exactly 250 ml.
For the preparation of 1 litre of M/10 oxalic acid solution, the amount of oxalic acid required is 3.15g.
(b) Titration of potassium permanganate solution against standard oxalic acid solution:
S. No |
Initial Reading (ml) |
Final Reading (ml) |
Volume of KMnO₄ used (V₂, ml) |
1 |
0 |
23.2 |
23.2 |
2 |
0 |
23.1 |
23.1 |
3 |
0 |
23.2 |
23.2 |
To find the strength (molarity) of the potassium permanganate (KMnO4) solution, we use the following formula based on the reaction between oxalic acid and KMnO4:
a1M1V1 = a2M2V2
To find the strength (molarity) of the potassium permanganate (KMnO4) solution, we use the following formula based on the reaction between oxalic acid and KMnO4:
Where
From the balanced equation, we know that the ratio of oxalic acid to KMnO₄ is 5:2, so we rearrange the formula to calculate the molarity of KMnO₄ (M₂):
M_2=\left(2 \times M_1 \times V_1\right) /\left(5 \times V_2\right)
From the balanced equation, we know that the ratio of oxalic acid to KMnO4 is 5:2, so we rearrange the formula to calculate the molarity of KMnO4 (M2):
Once we find the molarity of KMnO4, we can calculate its strength (in terms of molarity) by multiplying the molarity by the molar mass of KMnO4:
\text { Strength }=\text { Molarity } \times \text { Molar Mass }
This gives us the concentration of KMnO4 Solution, which is the goal of the titration.
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