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Which of the following smallest number should be added to 6659 to make it a perfect square?

This question was previously asked in
CSIR-CLRI JSA 2024 Official Paper-I (Held On: 16 Feb, 2025)
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  1. 230
  2. 65
  3. 98
  4. 56

Answer (Detailed Solution Below)

Option 2 : 65
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Detailed Solution

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Given:

Number = 6659

Formula used:

To find the smallest number to be added to make it a perfect square.

Calculations:

Nearest perfect square less than 6659 is 812 = 6561

⇒ Difference = 6659 - 6561 = 98

Nearest perfect square greater than 6659 is 822 = 6724

⇒ Difference = 6724 - 6659 = 65

∴ The correct answer is option 2.

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Latest CSIR Junior Secretariat Assistant Updates

Last updated on May 21, 2025

->The CSIR Junior Secretariat Assistant Provisional Response Sheet has been released on 21st May 2025 at the official website.

-> The CSIR Junior Secretariat Assistant Notification 2025 written examination dates has been released for Advt No. CRRI/02/PC/JSA-JST/2025.

-> Candidates had applied online from 22nd March to 21st April 2025.  

-> The CSIR JSA salary ranges from INR 19,900 - INR 63,200 (Indian Institute of Petroleum, Dehradun) and INR 35,600 (Indian Institute of Toxicology Research).

-> The selection of candidates for this post will be based on a Written Exam, followed by a Computer Typing Test.

-> Prepare for the exam with CSIR Junior Secretariat Assistant Previous Year Papers.

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