Question
Download Solution PDFWhich of the following function is a valid potential function (ϕ)?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
A function \( \phi(x, y) \) is a valid potential function if its mixed second-order partial derivatives are equal:
\( \frac{\partial^2 \phi}{\partial x \partial y} = \frac{\partial^2 \phi}{\partial y \partial x} \)
Check for Option:
\( \phi(x, y) = y^3 - 3x^2y \)
\( \frac{\partial \phi}{\partial x} = -6xy \Rightarrow \frac{\partial^2 \phi}{\partial x \partial y} = -6x \)
\( \frac{\partial \phi}{\partial y} = 3y^2 - 3x^2 \Rightarrow \frac{\partial^2 \phi}{\partial y \partial x} = -6x \)
Since the mixed partials are equal, the function is a valid potential function.
Last updated on Jul 15, 2025
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