What is this circuit?

F1 Shubham.B 19-01-21 Savita D2

This question was previously asked in
VSSC (ISRO) Technician B (Electronic Mechanic) Previous Year Paper (Held on 25 Sept 2016)
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  1. high-pass filter
  2. differentiator
  3. band pass filter
  4. low pass filter

Answer (Detailed Solution Below)

Option 4 : low pass filter
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Detailed Solution

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Given circuit:

F1 Shubham 22.3.21 Pallavi D 1

To check the behavior of the circuit analyze the given circuit at different frequencies.

\(\frac{{{V_{out}}}}{{{V_{in}}}} = \frac{{\frac{1}{{sc}}}}{{R + \frac{1}{{sc}}}}\)

\(\frac{{{V_{out}}}}{{{V_{in}}}} = \frac{1}{{sRC + 1}}\)

\({V_{out}} = \frac{1}{{sRC + 1}}{V_{in}}\)

\(\left| {\frac{{{V_{out}}}}{{{V_{in}}}}} \right| = \frac{1}{{\sqrt {1 + {\omega ^2}{R^2}{C^2}} }}\)

For ω = 0:

\(\left| {\frac{{{V_{out}}}}{{{V_{in}}}}} \right| = 1\)

For ω = ∞ (High frequency):

\(\left| {\frac{{{V_{out}}}}{{{V_{in}}}}} \right| = 0\)

Observation: The given circuit produces output for low frequencies. ∴ The given circuit is a low pass circuit.

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