Two long current-carrying wires are kept parallel at a distance 2r between them and if currents I and 2I respectively are flowing in these in same direction, the resultant magnetic field B at the mid-point between two wires is

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UP LT Grade Teacher (Science) 2018 Official Paper
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  1. \(3I \frac{\mu_0}{2\pi r}\)
  2. \(2I \frac{\mu_0}{2\pi r}\)
  3. \(I \frac{\mu_0}{4\pi r}\)
  4. \(I \frac{\mu_0}{2\pi r}\)

Answer (Detailed Solution Below)

Option 4 : \(I \frac{\mu_0}{2\pi r}\)
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Detailed Solution

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Concept Used:

  • The magnetic field due to a long straight current-carrying wire at a distance r is given by: B = (μ0 / 2π) × (I / r)
  • At the midpoint between two wires, the distance from each wire is r.
  • The net magnetic field is the vector sum of the fields produced by both wires.
  • Since the currents flow in the same direction, the magnitude of magnetic fields at the midpoint will subtract using thumb rule.

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Here, dot represent the direction of magnetic field into the page and cross represent the direction of magnetic field out of the page

Calculation:

Magnetic field due to the first wire at the midpoint:

B1 = (μ0 / 2π) × (I / r)

Magnetic field due to the second wire at the midpoint:

B2 = (μ0 / 2π) × (2I / r)

Net magnetic field at the midpoint:

Bnet = B1 - B2

⇒ Bnet = [(μ0 / 2π) × (I / r)] - [(μ0 / 2π) × (2I / r)]

∴ Bnet = I × (μ0 / 2πr)

Hence, the correct answer is Option 4: I (μ0 / 2πr).

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