The product (Z) of the following reaction is

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  1. qImage67c84d26d701aa791769641f
  2. qImage67c84d26d701aa7917696420
  3. qImage67c84d27d701aa7917696422
  4. qImage67c84d27d701aa7917696423

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Option 2 : qImage67c84d26d701aa7917696420
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AIIMS BSc NURSING 2024 Memory-Based Paper
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CONCEPT:

Friedel-Crafts Alkylation Reaction

  • The Friedel-Crafts alkylation is an electrophilic aromatic substitution reaction in which an alkyl group is added to an aromatic ring using an alkyl halide (like CH3Cl) and a Lewis acid catalyst (like AlCl3).
  • In this reaction, the alkyl halide (CH3Cl) reacts with the aromatic compound (benzene) in the presence of anhydrous AlCl3 to form a methylated product (toluene, C6H5CH3) and HCl as a byproduct.

EXPLANATION:

  • qImage6800fb74ecb407eec1a8b679
  • In the given reaction:

    C6H6 (benzene) + CH3Cl (methyl chloride) → C6H5CH3 (toluene) + HCl

  • The Lewis acid AlCl3 activates the methyl chloride (CH3Cl) by accepting a lone pair of electrons from the chlorine atom, which creates a methyl carbocation (CH3+), a highly reactive species.
  • The methyl carbocation (CH3+) then attacks the electron-rich benzene ring, resulting in the substitution of a hydrogen atom with a methyl group to form toluene (C6H5CH3).
  • The byproduct of this reaction is hydrochloric acid (HCl), which is released during the reaction.
  • The reaction follows the mechanism of electrophilic aromatic substitution.

Therefore, the product (Z) of the reaction is Toluene (C6H5CH3).

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