The observed time for an element is 2.4 minutes. The pace rating is 90 percent and the sum of all secondary adjustment amounts to 40 percent. The normal time is _______.

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Question

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JKSSB JE Mechanical 02 Nov 2021 Shift 1 Official Paper

Answer 1

Concept:

Normal time = \(\frac{{{\rm{Rating\;factor}}\left( {\rm{\% }} \right)}}{{100}}\) × observed time

Standard time = normal time × \(\left( {1 + \frac{{{\rm{allowance}}\left( {\rm{\% }} \right)}}{{100}}} \right)\)

Calculation:

Observed time = 2.4 min

Normal time = Observed time × Rating factor

= 2.4× 0.9 = 2.16 min

Standard time = Normal time \(\left( {1 + \frac{{\% \;allowances}}{{100}}} \right)\)

= 0.48 \(\left( {1 + \frac{{40}}{{100}}} \right)\) = 3.024 min