Question
Download Solution PDFThe input of an A.C. circuit having power factor of 0.8 lagging is 40 kVA. The power drawn by the circuit is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
\(kVA = \frac{{kW}}{{cos\phi }}\)
kVAR = (kVA) (sinϕ)
\(sin\phi = \sqrt {1 - {{\cos }^2}\phi } \)
Where,
kVA = Apparent power (S)
kW = Active/True power (P)
kVAR = Reactive power (Q)
cosϕ = Power factor
In an A.C. circuit, true power drawn by the circuit is given by:
True power = Apparent power × Power factor.
Calculation:
Here, input apparent power is 40 kVA and the power factor is 0.8
The power drawn by the circuit is:
(40 × 0.8) kW = 32 kW
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