The condition for a reversible cyclic process is

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  1. \(\oint\frac{\delta Q}{T}=0\)
  2. \(\oint\frac{\delta Q}{T}<0\)
  3. \(\oint\frac{\delta Q}{T}>0\)
  4. None of the above

Answer (Detailed Solution Below)

Option 1 : \(\oint\frac{\delta Q}{T}=0\)
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Detailed Solution

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Explanation:

\(\oint \frac{{dQ}}{T}\), represents entropy in a cyclic process.

Generally, \(\frac{{\partial Q}}{T} = {\rm{dS}}\)

and \(\oint \frac{{\partial Q}}{T}\) represents a cyclic integration of S and represented as \(\oint dS\)

\(\oint \frac{{\partial Q}}{T} \le \oint dS\) for any cycle.

Additional Information

As per Clausius Inequality

If \(\oint \frac{{\partial Q}}{T} = 0\) the cycle is reversible.

If \(\oint \frac{{\partial Q}}{T} < 0\) the cycle is irreversible.

If \(\oint \frac{{\partial Q}}{T} > 0\) the cycle is impossible.

Since entropy is a property, the cyclic integral of any property is zero

\(\oint \frac{{\partial Q}}{T} \le 0\)

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