Question
Download Solution PDFThe characteristic equation of the above closed-loop system is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Characteristic equation “q(s)” is Numerator part of 1 + G(s)H(s) = 0
Where G(s)H(s) is open loop transfer function
Let,
\(G\left( s \right)H\left( s \right) = \frac{{z\left( s \right)}}{{p\left( s \right)}}\) -----(1)
So, 1 + G(s)H(s) = 0 can be written as:
\(1 + \frac{{z\left( s \right)}}{{p\left( s \right)}} = 0\)
⇒ q(s) = p(s) + z(s) = 0 is characteristic equation. -----(2)
Analysis:
G(s) = 4 × (3/s+1)
H(s) = 10/(s+10)
The characteristic equation is given as:
1+ G(s) H(s) = 0
\(1 + (\frac{12}{s+1} \times \frac{10}{s+10}) = 0\)
(s+1)(s+10) + 120 = 0
s2 + 11s + 130 = 0
Last updated on Jun 23, 2025
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