Question
Download Solution PDF(a + b)2 = 36 మరియు ab = 8, అయితే (a – b)2 విలువ ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చినది:
(a + b)2 = 36 మరియు ab = 8
ఫార్ములా:
(a + b)2 - (a – b)2 = 4ab
లెక్కింపు:
(a + b)2 - (a – b)2 = 4ab
⇒ 36 – (a – b)2 = 4ab
⇒ (a – b)2 = 36 – 32
⇒ (a – b)2 = 4.
పద్ధతి 2
(a + b)2 = 36
⇒ a2 + b2 + 2ab = 36
⇒ a2 + b2 + 2 × 8 = 36
⇒ a2 + b2 = 20 ---- (1)
ఇప్పుడు, (a - b)2 = a2 + b2 - 2ab = 20 - 2 × 8 = 20 - 16 = 4.
చిన్న ఉపాయం
a = 4 మరియు b = 2 [(a + b)2 = (4 + 2)2 = 62 = 36 మరియు ab = 4 × 2 = 8]
∴ (a – b)2 = (4 – 2)2 = 22 = 4.
Last updated on Jul 22, 2025
-> RRB NTPC Undergraduate Exam 2025 will be conducted from 7th August 2025 to 8th September 2025.
-> The RRB NTPC UG Admit Card 2025 will be released on 3rd August 2025 at its official website.
-> The RRB NTPC City Intimation Slip 2025 will be available for candidates from 29th July 2025.
-> Check the Latest RRB NTPC Syllabus 2025 for Undergraduate and Graduate Posts.
-> The RRB NTPC 2025 Notification was released for a total of 11558 vacancies. A total of 3445 Vacancies have been announced for Undergraduate posts while a total of 8114 vacancies are announced for Graduate-level posts in the Non-Technical Popular Categories (NTPC).
-> Prepare for the exam using RRB NTPC Previous Year Papers.
-> HTET Admit Card 2025 has been released on its official site