Question
Download Solution PDFస్థూపం యొక్క ఎత్తు మరియు వక్ర ఉపరితల వైశాల్యం వరుసగా 10 సెం.మీ మరియు 440 సెంమీ2 . స్థూపం యొక్క వ్యాసం:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇవ్వబడింది:
స్థూపం యొక్క ఎత్తు = 10 సెం.మీ
స్థూపం యొక్క వక్ర ఉపరితల వైశాల్యం = 440 సెం.మీ2
సూత్రం:
స్థూపం యొక్క వక్ర ఉపరితల వైశాల్యం = 2πrh
లెక్క:
ప్రశ్న ప్రకారం
2πrh = 440
⇒ 2 × (22/7) × r × 10 = 440
⇒ r = 440 × (7/440)
⇒ r = 7 సెం.మీ
∴ స్థూపం యొక్క వ్యాసం = 2 × 7 = 14 సెం.మీ
Last updated on Jun 27, 2025
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