Question
Download Solution PDFOut of a group of three numbers, second is thrice of the first and also twice of the third. If the sum of the three numbers is 55 then find the largest number in the group.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFLet three numbers be a, b and c
Now, b = 3a
⇒ a = b/3 ----(1)
And, b = 2c
⇒ c = b/2 ----(2)
Now,
Sum of three numbers = 55
⇒ a + b + c = 55
⇒ (b/3) + b + (b/2) = 55
⇒ 11b/6 = 55
⇒ b = 30
So, a = b/3 = 30/3 = 10
And, c = b/2 = 30/2 = 15
∴ Largest number is 30
Shortcut TrickIt is given in the question that the second number is three times the first number and twice the third number. It means it will be divisible by both 3 and 2. Hence our answer should be divisible with 6. Only 30 from the given numbers is divisible by 6.
∴ The largest number is 30.
Last updated on Jul 10, 2025
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