Question
Download Solution PDFInsertion of a record in a circularly linked list involves the modification of:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFIt will require modification of 2 pointers, next of node N1 after which insertion is to be done and next of new node.
We can understand by given example-
Consider ACLL having 4 Nodes A, B, C, D
A New Node E is inserted between B & C:
So 2 pointer modification required.
Last updated on Jun 23, 2025
-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.