Question
Download Solution PDFIf cosec A - cot A = \(\frac{1}{4}\), then the value of tan A is :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
cosec A - cot A = \(\frac{1}{4}\)
Concept used:
1. cosec2 A - cot2 A = 1
2. cot A = 1 ÷ tan A
Calculation:
cosec A - cot A = \(\frac{1}{4}\) ....(1)
According to the concept,
cosec2 A - cot2 A = 1
⇒ (cosec A + cot A)(cosec A - cot A) = 1
⇒ (cosec A + cot A) × \(\frac{1}{4}\) = 1
⇒ (cosec A + cot A) = 4 ....(2)
Now, (2) - (1),
2cot A = 4 - 1/4
⇒ cot A = 15/8
⇒ tan A = 8/15
∴ The required value of tan A is \(\frac{8}{15}\).
Last updated on Jun 25, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.
->The UGC NET Exam Analysis 2025 for June 25 is out for Shift 1.