Testbook Logo
Exams SuperCoaching Test Series Skill Academy
More
English
Hindi

Question

Download Solution PDF

If a zero is added in a forward path of a second-order system:

This question was previously asked in
LMRC Assistant Manager (S&T) Official Paper: (Held on 20 Jan 2020)
Download PDF Attempt Online
View all LMRC AM Papers >
  1. rise time will decrease
  2. rise time will increase
  3. bandwidth will decrease
  4. system will be less stable 

Answer (Detailed Solution Below)

Option 1 : rise time will decrease

Detailed Solution

Download Solution PDF

Effect of addition of zero:

  • It attracts root locus branches away from the jω-axis, due to which the system becomes more stable.
  • Relative stability improves.
  • The system becomes less oscillatory.
  • As the rise time is inversely proportional to speed, the rise time will decrease.
  • Also, because the bandwidth is inversely proportional to the rise time, so the bandwidth increases.

 

Effect of addition of poles:

  • It attracts root locus branches towards the jω-axis due to which the system becomes less stable.
  • The relative stability reduces.
  • The system becomes more oscillatory.
  • As the rise time is inversely proportional to speed, so the rise time will increase.
  • Also, because the bandwidth is inversely proportional to the rise time, so the bandwidth decreases.
Download Solution PDF
Latest LMRC AM Updates

Last updated on Jun 9, 2024

-> UPMRC Assistant Manager Result has been released.

-> The exam was conducted on 11th, 12th, and 14th May 2024. The provisionally selected candidates will be called for DV and Medical examination.

-> Eligible candidates had applied online from 20th March to 19th April 2024.

-> A total of 31 vacancies have been announced.

-> Eligible candidates can apply online from 20th March to 19th April 2024.

-> The UPMRC Assistant Manager Selection Process consists of three stages - computer-Based Test, Document verification, and a Medical examination.

-> The salary of the finally appointed candidates will be in the pay scale of Rs. 50,000 to Rs. 1,60,000.

More Time Response of the First and Second Order System Questions

Q1.A second-order system has a transfer function given by G(s)=25s2+8s+25. If the system, initially at rest, is subjected to a unit-step input at t = 0, the second peak in the response will occur at
Q2.The unit step response of a system is [1 − e−t(1 + t)] u(t). The system is
Q3.Response of the first order system subjected to unit step input is given by -
Q4.The impulse response of an LTI system is given as : h[n]={ωcπn=0 sin⁡ωcnπnn≠0 It represents an ideal
Q5.The impulse response of a system is h(t) = t u(t) . For an input u(t - 1) , the output is
Q6.In control systems, if 'G' is the gain then Damping varies with:
Q7.Two discrete time systems with impulse responses ht[n] = δ[n - 1] and h2[n] = δ[n - 2]  are connected in cascade. The overall impulse response of the cascaded system is
Q8.Direction: Question consists of two statements, one labelled as the 'Assertion (A)' and the other as 'Reason (R)'. Examine these two statements carefully and select the answer to this question using the codes given below: Assertion (A): A linear system gives a bounded output if the input is bounded. Reason (R): The roots of the characteristic equation have all negative real parts and the response due to initial conditions decay to zero as time t tends to infinity.
Q9.If the response of LTI continuous time system to unit step input is (12−12e−2t), then impulse response of the system is

More Time Response Analysis Questions

Q1.A unity feedback system is characterized by the open-loop transfer function G(s)=100s(5s+10)(2s+10) The steady-state errors for unit-step and unit-ramp inputs are :
Q2.In the circuit shown switch is closed at t = 0. The time constant of the circuit is :
Q3.Consider a causal second-order system with the transfer function G(s)=1s2+2s+1 with a unit-step R(s)=1s as an input. Let c(s) be the corresponding output. The time taken by the system output c(t) to reach 94% of its steady-state value limt→∞c(t), rounded off to two decimal places, is
Q4.The output of a standard second-order system for a unit-step input is given as y(t)=1−23e−tcos⁡(3t−π6). What is the transfer function of the system?
Q5.A second-order system has a closed-loop transfer function given by G(s)=25s2+8s+25. The settling time for 5 percentage band in tolerance error is
Q6.A second-order system has a transfer function given by G(s)=25s2+8s+25. If the system, initially at rest, is subjected to a unit-step input at t = 0, the second peak in the response will occur at
Q7.Steady state error is the value of error signal when:
Q8.A closed loop system is shown in the figure where k > 0 and α > 0. The steady state error due to a ramp input (R(s) = α/s2) is given by 
Q9.The nature of the response shown below is:
Q10.When the damping ratio ζ (zeta) lies in between 0 < ζ < 1, then the circuit classification comes under:
Suggested Test Series
View All >
AE & JE Civil Engg. Exams Previous Year Papers Mock Test
469 Total Tests with 3 Free Tests
Start Free Test
AE & JE Electrical Engg. Exams Previous Year Papers Mock Test
276 Total Tests with   3 Free Tests
Start Free Test
Suggested Exams
Exam-Logo
TANGEDCO Assistant Engineer
Exam-Logo
LMRC AM

TANGEDCO Assistant Engineer Important Links

More Control Systems Questions

Q1.A unity feedback system is characterized by the open-loop transfer function G(s)=100s(5s+10)(2s+10) The steady-state errors for unit-step and unit-ramp inputs are :
Q2.In the circuit shown switch is closed at t = 0. The time constant of the circuit is :
Q3.The loop transfer function of a closed-loop control system is given as : G(s)H(s)=k(s+1)s(s+2)(s+3) The centroid of the asymptotes in root locus is :
Q4.For a control system having fourteen poles and two zeros, the slope in its magnitude plot for high frequency asymptote will be :
Q5.The Routh Array is as below : S6182016S521216S421216S300 The row of zero of this array will be replaced by coefficients of 
Q6.The number of roots in the left half of the s-plane for a system having characteristic equations : s3 + 5s2 + 7s + 3 = 0 is : 
Q7.Explain the pattern and trend of public expenditure on social services in the post reforms period in India. To what extent this has been in consonance with achieving objective of inclusive growth? 
Q8.The Nyquist criterion for stability states that an amplifier is unstable if the Nyquist curve encloses the -1 + j0 point, and the amplifier is stable if the curve does not enclose this point. If Aβ
Q9.The phase margin of a system with the open-loop transfer function G(s)H(s)=1−s(s+1)(s+2) is
Q10.The phase margin of a system having the loop transfer function G(s)H(s)=23s(s+1) is
Important Exam
Super Coaching
Exams
Previous Year Papers
Test Series
Objective Questions
Testbook Edu Solutions Pvt. Ltd.
1st & 2nd Floor, Zion Building,
Plot No. 273, Sector 10, Kharghar,
Navi Mumbai - 410210
support@testbook.com
Toll Free:1800 833 0800
Office Hours: 10 AM to 7 PM (all 7 days)
Company
About usCareers We are hiringTeach Online on TestbookPartnersMediaSitemap
Products
Test SeriesTestbook PassOnline CoursesOnline VideosPracticeBlogRefer & EarnBooks
Our Apps
Follow us on
Copyright © 2014-2022 Testbook Edu Solutions Pvt. Ltd.: All rights reserved
User PolicyTermsPrivacy
Get Free Access Now
Hot Links： teen patti master plus teen patti earning app online teen patti teen patti joy