If 2p + 5q = 12 and pq = 3, find the value of 4p2  + 25q2

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SSC CHSL Tier-I Exam 2022 Official Paper (Held On: 10 March, 2023 Shift 2)
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  1. 64
  2. 24
  3. 84
  4. 44

Answer (Detailed Solution Below)

Option 3 : 84
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Detailed Solution

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Calculation:

We have:

2p + 5q = 12 ........(1)

pq = 3 ........(2)

Squaring equation (1), we get:
\(4p^2 + 20pq + 25q^2 = 144\)

Substituting the value of pq from equation (2), we get:
\(4p^2 + 20(3) + 25q^2 = 144\)

Simplifying this equation:

\(4p^2 + 25q^2 = 84\)

Therefore, the value of \(4p^2 + 25q^2\) is 84.

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