Question
Download Solution PDFकिसी रैखिक समय-अपरिवर्तनीय निरंतर-समय प्रणाली का प्रणाली आव्यूह \(A\left[ {\begin{array}{*{20}{c}} 0&1\\ { - 4}&{ - 5} \end{array}} \right]\)द्वारा दिया जाता है। अभिलक्षण समीकरण के मूलों के मान क्या होगें?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFपरिकल्पना :
अभिलक्षण समीकरण के मूल के लिए :
[ sI - A ] = 0
जहाँ
I = इकाई आव्यूह
\({\rm{I}} = \left[ {\;\begin{array}{*{20}{c}} 1&0\\ 0&1 \end{array}} \right]\)
A = दिया गया आव्यूह
व्याख्या:
दिया है
\(A=\left[ {\begin{array}{*{20}{c}} 0&1\\ { - 4}&{ - 5} \end{array}} \right]\)
अभिलक्षण समीकरण के मूल के लिए:
[sI - A] = 0
\({\left[ {\left[ {\begin{array}{*{20}{c}} s&0\\ 0&s \end{array}} \right] - \left[ {\begin{array}{*{20}{c}} 0&1\\ -4&-5 \end{array}} \right]} \right]^{ }}=0\)
\(\left[ {\begin{array}{*{20}{c}} s&-1\\ { 4}&{ s+ 5} \end{array}} \right]=0\)
s( s + 5 ) + 4 = 0
s2 + 5s + 4 = 0
( s+4 )( s+1 ) = 0
s = -4, -1
Last updated on Jul 2, 2025
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