Question
Download Solution PDF8x + 3y = 24, 2x + 8 = y और x-अक्ष द्वारा बनने वाले त्रिभुज का क्षेत्रफल (वर्ग इकाई में) क्या है?:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया है:
8x + 3y = 24, 2x + 8 = y और x-अक्ष
प्रयुक्त सूत्र:
त्रिभुज का क्षेत्रफल = 1/2 × आधार × ऊंचाई
दो रेखाओं 8x + 3y = 24, 2x + 8 = y के प्रतिच्छेदन बिंदु का Y निर्देशांक त्रिभुज की ऊंचाई देता है।
रेखाओं 8x + 3y = 24, 2x + 8 = y के x अन्तः-खंड का अंतर त्रिभुज का आधार देता है।
गणना:
8x + 3y = 24, 2x + 8 = y का प्रतिच्छेदन बिंदु ज्ञात करने के लिए एक समीकरण को दूसरे में रखते हैं।
⇒ 8x + 3(2x + 8) = 24
⇒ 14x = 0
⇒ x = 0
⇒ y = 2×0 + 8 = 8
⇒ त्रिभुज की ऊंचाई = 8
8x + 3y = 24, 2x + 8 = y के लिए X – अन्तः-खंड ज्ञात करने के लिए y = 0 रखते हैं
⇒ 8x + 3×0 = 24
⇒ x1 = 3
⇒ 2x + 8 = 0
⇒ x2 = -4
इनका अंतर आधार है = 3 – (-4) = 7
∴ त्रिभुज का क्षेत्रफल = 8 × 7/2 = 28
Last updated on Jul 21, 2025
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