Question
Download Solution PDFदी गयी आकृति में, ABCD एक वर्ग है। यदि वृत्त की त्रिज्या 5 सेमी है, तो स्पर्शरेखाएँ PC की लंबाई ज्ञात कीजिये।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFवृत्त की त्रिज्या 5 सेमी है
∴ वर्ग AB की भुजा = BC = 5√2 सेमी
माना, PB = x सेमी
ΔPBC में,
⇒ PC2 = [(5√2)2 + x2]
हम जानते हैं कि∶
PC2 = PB × PA
⇒ [(5√2)2 + x2] = x × (x + 5√2)
⇒ 50 + x2 = x2 + 5√2x
⇒ x = 5√2 सेमी
∴ PC = √[(5√2)2 + x2] = √(50 + 50) = 10 सेमीLast updated on Jul 9, 2025
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