यदि 21a + 21b = 1134 है, तो a + b का औसत क्या है?

This question was previously asked in
CSIR-CLRI JSA 2024 Official Paper-I (Held On: 16 Feb, 2025)
View all CSIR Junior Secretariat Assistant Papers >
  1. 29
  2. 27
  3. 58
  4. 54

Answer (Detailed Solution Below)

Option 2 : 27
Free
CSIR JSA General Awareness Mock Test
20 Qs. 60 Marks 12 Mins

Detailed Solution

Download Solution PDF

दिया गया है:

21a + 21b = 1134

प्रयुक्त सूत्र:

a + b का औसत = (a + b)/2

गणना:

21(a + b) = 1134

⇒ a + b = 1134/21

⇒ a + b = 54

a + b का औसत = 54/2

⇒ a + b का औसत = 27

∴ सही उत्तर विकल्प (2) है।

Latest CSIR Junior Secretariat Assistant Updates

Last updated on Jun 24, 2025

-> The CSIR Junior Secretariat Assistant 2025 has been released for 9 vacancies.

-> Candidates can apply online from 17th June to 7th July 2025.  

-> The CSIR JSA salary ranges from INR 19,900 - INR 63,200 (Indian Institute of Petroleum, Dehradun & Institute of Microbial Technology) and INR 35,600 (Indian Institute of Toxicology Research).

-> The selection of candidates for this post will be based on a Written Exam, followed by a Computer Typing Test.

-> Prepare for the exam with CSIR Junior Secretariat Assistant Previous Year Papers.

More Average Questions

Hot Links: teen patti master plus teen patti - 3patti cards game teen patti 100 bonus teen patti 50 bonus teen patti star login