(1, -1) पर वक्र y2 - 3x3 + 2 = 0 की स्पर्श रेखा की ढलान ज्ञात कीजिए। 

  1. -1.5
  2. 2.5
  3. 3.5
  4. -4.5

Answer (Detailed Solution Below)

Option 4 : -4.5
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संकल्पना:

वक्र y = f(x) के लिए स्पर्श रेखा का ढलान m = \(\rm dy\over dx\) है। 

लम्बवत का ढलान = \(\rm -{1\over m}\) = \(\rm -{1\over {dy\over dx}}\)

गणना:

दिया गया है वक्र y2 - 3x3 + 2 = 0

x के संबंध में समीकरण का अवकलन करने पर 

⇒ 2y\(\rm dy\over dx\) - 9x2 + 0 = 0

⇒ 2y   = 9x2

(1, -1) पर ढलान 

2(-1) \(\rm dy\over dx\) = 9 (1)

⇒ -2\(\rm dy\over dx\) = 9

⇒ \(\rm dy\over dx\) = -4.5

स्पर्श रेखा का ढलान (m) = \(\rm {dy\over dx}\)

∴ m = -4.5

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