Question
Download Solution PDF(1, -1) पर वक्र y2 - 3x3 + 2 = 0 की स्पर्श रेखा की ढलान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
वक्र y = f(x) के लिए स्पर्श रेखा का ढलान m = \(\rm dy\over dx\) है।
लम्बवत का ढलान = \(\rm -{1\over m}\) = \(\rm -{1\over {dy\over dx}}\)
गणना:
दिया गया है वक्र y2 - 3x3 + 2 = 0
x के संबंध में समीकरण का अवकलन करने पर
⇒ 2y\(\rm dy\over dx\) - 9x2 + 0 = 0
⇒ 2y = 9x2
(1, -1) पर ढलान
2(-1) \(\rm dy\over dx\) = 9 (1)
⇒ -2\(\rm dy\over dx\) = 9
⇒ \(\rm dy\over dx\) = -4.5
स्पर्श रेखा का ढलान (m) = \(\rm {dy\over dx}\)
∴ m = -4.5
Last updated on Jun 20, 2025
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