एक 8-ध्रुव जनरेटर में 500 V पर 200 A का आउटपुट होता है, लैप-संयोजित आर्मेचर में 1280 चालक, 160 दिक्परिवर्तक खंड होते हैं। यदि ब्रश शून्य भार उदासीन अक्ष से 4-खंड एडवांस हैं, तो क्रॉस-चुबंकीय एम्पीयर-फेरे प्रति ध्रुव क्या है?

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ESE Electrical 2021 Official Paper
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  1. 1600
  2. 1400
  3. 1550
  4. 1200

Answer (Detailed Solution Below)

Option 4 : 1200
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संकल्पना:

DC जनरेटर में:

क्रॉस-चुबंकीय एम्पीयर फेरे \(\left( A{{T}/P} \right)=\frac{Z/2}{P}(1-\frac{2β}{180})(\frac{I_a}{A})\)

जहाँ,

Z = चालकों की कुल संख्या

Ia = आर्मेचर धारा (Ia)

A = समानांतर पथों की संख्या

β= ब्रश शिफ्ट कोण

P = ध्रुवों की संख्या

गणना​:

P = 8, Z = 1280, Ia = 200 A,

दिया गया है, 160 दिक्परिवर्तक खंड,

इसलिए, βm = \(\frac{360}{160}× 4=9^\circ\)

अब β = β× \(\frac{P}{2}\) = 9 × 4 = 36°

A = P = 8 (लैप कुंडली के लिए)

क्रॉस-चुबंकीय एम्पीयर फेरे \(\left( A{{T}/P} \right)=\frac{1280/2}{8}(1-\frac{2× 36}{180})(\frac{200}{8})\) = 1200

 
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