For a multiplier with one signal input having a peak voltage of 5 mV and a frequency 1200 kHz and the other input having a peak voltage of 10 mV and a frequency of 1655 kHz, the output expression for this multiplier is: 

Analog multiplier circuit

In electronics, an analog multiplier is a device that takes two analog signals and produces an equivalent output.

The output voltage of the multiplier circuit is:

\(V=V_1+V_2\)

The output frequency is:

\(f=f_1-f_2\) and \(f=f_1+f_2\)

Calculation

Given, V₁ = 10 mV at f₁ = 1655 kHz

V₂ = 5 mV at f₂ = 1200 kHz

\(V=10+5=15\space mV\)

\(f=f_1-f_2\)

\(f=1655-1200=455 \space kHz\)

\(f=f_1+f_2\)

\(f=1655+1200=2855 \space kHz\)

Hence, the output of the multiplier circuit is:

V_o = 15 mV cos 2π (455 kHz) t + 15 mV cos 2π (2855 kHz) t