Question
Download Solution PDFFor 30° cranked or bent-up bar, the inclined length of the crank is given by:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Bars are bent near the support at an angle of 45°.
The angle of bend may also be 30° in shallow beams.
The purpose of bend near the support is firstly to resist the negative bending moment which occurs in the region of the support and secondly to resist the shear force which is greater at the support.
Inclined length of cranked bar is equal to:
\({\rm{L}} = \frac{{\rm{d}}}{{\sin 30}} = 2{\rm{d}}\)
Where,
d = overall depth of the beam/ member – top cover – bottom cover – bar diameter
Last updated on Jun 4, 2025
-> OSSC JE Preliminary Fiinal Answer Key 2025 has been released. Applicants can raise objections in OSSC JE answer key till 06 June 2025.
-> OSSC JE prelim Exam 2025 was held on 18th May 2025.(Advt. No. 1233/OSSC ).
-> The OSSC JE 2024 Notification was released for 759 vacancies through OSSC CTSRE 2024.
-> The selection is based on the written test. This is an excellent opportunity for candidates who want to get a job in the Engineering sector in the state of Odisha.
-> Candidates must refer to the OSSC JE Previous Year Papers to understand the type of questions in the examination.