Find the voltage at node 'a' in the given circuit.

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MPPGCL JE Electrical 19 March 2019 Shift 2 Official Paper
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  1. Va = 8 V
  2. Va = 16 V
  3. Va = 32 V
  4. Va = 3 V

Answer (Detailed Solution Below)

Option 2 : Va = 16 V
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Detailed Solution

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Concept

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Assume the voltage at node 'a' is Va

\({V_a+12\over 10}-3+{V_a-8\over 40}=0\)

\({V_a+12\over 10}+{V_a-8\over 40}=3\)

\({4V_a+48+V_a-8\over 40}=3\)

\({4V_a+48+V_a-8}=120\)

\(5V_a=120-48+8\)

Va = 16 V

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