Question
Download Solution PDFFind the arithmetic mean of the below case
Monthly wage |
Number of workers |
700 |
2 |
800 |
8 |
900 |
8 |
1000 |
2 |
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Concept:
Arithmetic Mean:
- The arithmetic mean is the sum of a collection of numbers divided by the count of numbers in the collection.
- Given a data set X = {x1, x2, x3, .... xn}, the arithmetic mean is denoted by \(\bar{x}\) .
\(\bar{x} = \frac{1}{n}\times \sum_{i=1}^{n}x_i\)
- For calculating the mean when the frequency of the observations is given, such that x1, x2, x3, … xn is the recorded observations, and f1, f2, f3 … fn is the respective frequencies of the observations then
\(\bar{x} = \frac{\sum_{i=1}^{n}f_ix_i} {\sum_{i=1}^{n}f_i}\)
Calculation:
Data given, we take monthly wage as dataset and number of workers as frequency data points,
x1 = 700, f1 = 2
x2 = 800, f2 = 8
x3 = 900, f3 = 8
x4 = 1000, f4 = 2
\(\bar{x} = \frac{(700\times2+800\times8+900\times8+1000\times2)} {(2+8+8+2)}\)
∴ \(\bar{x} = \frac{17000}{20} = 850\)
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