Question
Download Solution PDFযদি \(\left(\mathrm{k}+\frac{1}{\mathrm{k}}\right)^2=9\) হয়, তবে \(\mathrm{k}^3+\frac{1}{\mathrm{k}^3}\) এর মান কত নির্ণয় করুন।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
(k + 1/k)2 = 9
অনুসৃত সূত্র:
(k3 + 1/k3) = (k + 1/k)3 - 3(k + 1/k)
গণনা:
(k + 1/k)2 = 9
k + 1/k = 3
(k3 + 1/k3) = (k + 1/k)3 - 3(k + 1/k)
(k3 + 1/k3) = (3)3 - 3(3)
(k3 + 1/k3) = 27 - 9
(k3 + 1/k3) = 18
∴ সঠিক উত্তর বিকল্প 2.
Last updated on Jul 22, 2025
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