Question
Download Solution PDFAn unpolarized light beam is incident on the polarizer of a polarization experiment and the intensity of light beam emerging from the analyzer is measured as 100 Lumens. Now, if the analyzer is rotated around the horizontal axis (direction of light) by 30° in clockwise direction, the intensity of emerging light will be _________ Lumens.
Answer (Detailed Solution Below) 75 - 75.001
Detailed Solution
Download Solution PDFConcept:
When an unpolarized light beam is passed through a polarizer then the analyzer
it becomes polarized light with half intensity then its initial value is given as,
⇒ \( I = I_{o} (\cos θ )^{2}\) ----(1)
where, Io = intensity of unpolarized light
θ = angle of the polarizer
I = intensity of light after emerging
Calculation:
Given:
The angle between polarizer and analyzer is = 30o
The intensity of incident light is Io = 100 Lumens
we can write equation (1) as:
\(I = I_{o} (\cos \theta )^{2}\) => I = Io × (cos30)2
I = 100× \((\frac{\sqrt{3}}{2})^{2} = 3/4\) × 100 = 75 lumens
Last updated on May 23, 2025
-> JEE Main 2025 results for Paper-2 (B.Arch./ B.Planning) were made public on May 23, 2025.
-> Keep a printout of JEE Main Application Form 2025 handy for future use to check the result and document verification for admission.
-> JEE Main is a national-level engineering entrance examination conducted for 10+2 students seeking courses B.Tech, B.E, and B. Arch/B. Planning courses.
-> JEE Mains marks are used to get into IITs, NITs, CFTIs, and other engineering institutions.
-> All the candidates can check the JEE Main Previous Year Question Papers, to score well in the JEE Main Exam 2025.