An electrical circuit provides effective impedance of -2jΩ. What will be the phase difference between voltage and current in this circuit?

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HPCL Engineer Instrumentation 11 Aug 2021 Official Paper
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  1. 45°
  2. -90°
  3. 180°

Answer (Detailed Solution Below)

Option 2 : -90°
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Detailed Solution

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Concept:

Impedance in the alternating current circuit is defined as the net opposing factor to the flow of current.

This opposition may be due to Resistance & Inductance or Resistance & Capacitance or Resistance, Inductance and Capacitance.

It is denoted by the symbol Z.

Z is often expressed as Z = R+jX

\(Z = \frac{V∠ θ_{v}}{I∠ θ_{i}} = R + jX\)

\(|Z|∠ θ = \left |\frac{V }{I } \right |∠ (θ_{v} -θ_{i} ) = \sqrt{R^{2} + X^{2} }∠\tan^{-1}\left ( \frac{X}{R} \right )\)

Calculation:

Given;

Z = -2jΩ = 2∠-90° 

θv - θi= -90°

∴  phase difference between voltage and current is -90°

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