Question
Download Solution PDFAn electrical circuit provides effective impedance of -2jΩ. What will be the phase difference between voltage and current in this circuit?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Impedance in the alternating current circuit is defined as the net opposing factor to the flow of current.
This opposition may be due to Resistance & Inductance or Resistance & Capacitance or Resistance, Inductance and Capacitance.
It is denoted by the symbol Z.
Z is often expressed as Z = R+jX
\(Z = \frac{V∠ θ_{v}}{I∠ θ_{i}} = R + jX\)
\(|Z|∠ θ = \left |\frac{V }{I } \right |∠ (θ_{v} -θ_{i} ) = \sqrt{R^{2} + X^{2} }∠\tan^{-1}\left ( \frac{X}{R} \right )\)
Calculation:
Given;
Z = -2jΩ = 2∠-90°
θv - θi= -90°
∴ phase difference between voltage and current is -90°
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