Question
Download Solution PDFA voltage of V = 150 < 60° V is applied to a load which carries a current of I = 50 < 30° A. The complex power supplied to the load is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPower in an AC circuit
The complex power in an AC circuit is defined as the product of phasor voltage and conjugate of phasor current.
S = V × I*
where, S = Complex power
V = Voltage
I* = Conjugate of current
Calculation
Given, V = 150∠60°
I = 50∠30°
S = (150∠60°) (50∠30°)*
S = (150∠60°) (50∠-30°)
S = 7.5∠30° kVA
Last updated on May 29, 2025
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