Question
Download Solution PDFA vessel of capacity 3 m3 contains 1 kg mole of Nitrogen at 90°C. Characteristic gas constant, R for nitrogen (molecular weight, M 28) is 296.9 J/ kg K. The pressure and specific volume of the gas will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
We use the ideal gas law to determine the pressure and specific volume of nitrogen gas under given conditions.
Given:
- Volume of vessel, \( V = 3 \, \text{m}^3 \)
- Amount of gas, \( n = 1 \, \text{kg mole} \)
- Temperature, \( T = 90^\circ \text{C} = 363.15 \, \text{K} \)
- Characteristic gas constant for nitrogen, \( R = 296.9 \, \text{J/kg K} \)
- Molecular weight of nitrogen, \( M = 28 \, \text{kg/kmol} \)
Step 1: Calculate the universal gas constant (Ru)
The universal gas constant is related to the characteristic gas constant by:
\( R_u = R \times M = 296.9 \times 28 = 8313.2 \, \text{J/kmol K} \)
Step 2: Determine the pressure using ideal gas law
The ideal gas law is given by:
\( P V = n R_u T \)
Substituting the values:
\( P = \frac{n R_u T}{V} = \frac{1 \times 8313.2 \times 363.15}{3} \)
\( P = 1,006,000 \, \text{Pa} = 10.06 \, \text{bar} \)
Step 3: Calculate the specific volume
Specific volume (\( v \)) is the volume per unit mass:
\( v = \frac{V}{m} \)
Mass of nitrogen:
\( m = n \times M = 1 \times 28 = 28 \, \text{kg} \)
Thus:
\( v = \frac{3}{28} = 0.107 \, \text{m}^3/\text{kg} \)
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