A type of amplitude modulation in which carrier is suppressed is called

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IPRC (ISRO) Technician B (Electronics) 2018 Official Paper (Held on 22 April 2018)
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  1. Unbalanced Modulation
  2. Frequency Modulation
  3. Balanced Modulation
  4. Exponential Modulation

Answer (Detailed Solution Below)

Option 3 : Balanced Modulation
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Detailed Solution

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In a balanced modulator, 2 AM-modulators are connected in a way that the resultant signal does not contain the carrier spectrum, i.e. to generate a Double Side-band suppressed carrier (DSB-SC).

Analysis:

The circuit diagram of a balanced modulator is as shown:

F1 S.B 8.5.20 Pallavi D4

\( {s_{AM'}}\left( t \right) = {A_c}\left[ {1 + {k_a}m\left( t \right)} \right]\cos 2\pi {f_c}t\)

\(\\ {s_{AM''}}\left( t \right) = {A_c}\left[ {1 - {k_a}m\left( t \right)} \right]\cos 2\pi {f_c}t\)

The resultant DSB signal is the difference of the two, i.e.

\({s_{DSB}}\left( t \right) = {s_{AM'}}\left( t \right) - {s_{AM''}}\left( t \right) \)

Hence,

\({s_{DSB}}\left( t \right) = \;2{A_c}{k_a}m\left( t \right)\cos 2\pi {f_c}t\)

\( {s_{DSB}}\left( t \right) = \;{A_c}'m\left( t \right)\cos 2\pi {f_c}t\)

The frequency spectrum of the DSB-SC signal:

The standard DSB-SC equation is given as:

\({S_{DSB}}\left( t \right) = \;{A_c}m\left( t \right)\cos 2\pi {f_c}t\)

Assuming a single tone message signal as:

\(m\left( t \right) = \;{A_m}\cos 2\pi {f_m}t\)

The DSB-SC signal can be written as:

\({S_{DSB}}\left( t \right) = \frac{{{A_c}{A_m}}}{2}\cos 2\pi ({f_c} + {f_m})t + \;\frac{{{A_c}{A_m}}}{2}\cos 2\pi ({f_c} - {f_m})t\)

∴ The output of balanced modulator contains the modulation frequency, LSB and USB.

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