Pulse Analog Modulation MCQ Quiz in తెలుగు - Objective Question with Answer for Pulse Analog Modulation - ముఫ్త్ [PDF] డౌన్‌లోడ్ కరెన్

Concept:

The Bandwidth of resultant modulated signal is given by:

$\mathrm{B}.\mathrm{W}=\frac{{\mathrm{R}}_{\mathrm{b}}\left(1+\alpha \right)}{{\log }_2\mathrm{M}}$

where α is the roll off factor

Calculation:

Bit rate $=\underset{\mathrm{s}\mathrm{a}\mathrm{m}\mathrm{p}\mathrm{l}\mathrm{i}\mathrm{n}\mathrm{g}}{\underbrace{2\times {\mathrm{f}}_{\mathrm{m}}\times }}\underset{\mathrm{Q}\mathrm{u}\mathrm{a}\mathrm{n}\mathrm{t}\mathrm{i}\mathrm{z}\mathrm{i}\mathrm{n}\mathrm{g}}{\underset{\downarrow }{\underbrace{\mathrm{n}}}}$

$n={\log }_2^{256}=8$

R_b = 2 × 5 × 8 = 80

All these factors responsible for high signal to noise ratio:

1. There is less noise at frequencies at which FM is used.
2. Amplitude limiter are incorporated in FM receivers.
3. Interference from other FM transmitter is very less.