Electric Drives MCQ Quiz in தமிழ் - Objective Question with Answer for Electric Drives - இலவச PDF ஐப் பதிவிறக்கவும்

Last updated on Apr 16, 2025

பெறு Electric Drives பதில்கள் மற்றும் விரிவான தீர்வுகளுடன் கூடிய பல தேர்வு கேள்விகள் (MCQ வினாடிவினா). இவற்றை இலவசமாகப் பதிவிறக்கவும் Electric Drives MCQ வினாடி வினா Pdf மற்றும் வங்கி, SSC, ரயில்வே, UPSC, மாநில PSC போன்ற உங்களின் வரவிருக்கும் தேர்வுகளுக்குத் தயாராகுங்கள்.

Latest Electric Drives MCQ Objective Questions

Top Electric Drives MCQ Objective Questions

Electric Drives Question 1:

The motor preferred for boom hoist in case of travelling cranes is

  1. AC slip ring motor
  2. Squirrel cage induction motor
  3. Synchronous motor
  4. Ward Leonard controlled DC shunt motor

Answer (Detailed Solution Below)

Option 1 : AC slip ring motor

Electric Drives Question 1 Detailed Solution

For hoisting and lowering of crane requires high starting torque. Hence AC slip ring induction motor is preferred.

Electric Drives Question 2:

Which is not the main component of Electrical Drives?

  1. Positive feedback
  2. Machine
  3. Controller
  4. Power module

Answer (Detailed Solution Below)

Option 1 : Positive feedback

Electric Drives Question 2 Detailed Solution

The main components of electric drive are:

  • Power source
  • Power modulator
  • Electrical motors
  • Load
  • Control unit
  • Sensing unit


Positive feedback is not the main component of electrical drives.

Electric Drives Question 3:

Determine the suitable size of a continuously rated motor for the following load curve. The load has a repeated pattern every 30 min.

F1 U.B Madhu 22.01.20 D 14

  1. 81 kW
  2. 51 kW
  3. 77 kW
  4. 67 kW

Answer (Detailed Solution Below)

Option 4 : 67 kW

Electric Drives Question 3 Detailed Solution

F1 J.P 21.7.20 Pallavi D 2

F1 J.P 21.7.20 Pallavi D3

The suitable side of the motor can be calculated with the formula of 

L = \(\sqrt\frac{{L_1}^2 \times{t_1} + {L_2}^2 \times{t_2} + .....}{T}\)

where t1, t2 ...tn are the time for the individual loads

L1 , L2 ....are loads

T = total time period for one cycle

​Putting the value of L1 , L2 , t1, t2 and T in the formula we get

L = \(\sqrt\frac{{100}^2 \times{10} + {50}^2 \times{10} + .....}{30}\)

= 64.65 KW

which is nearly equal to 67 KW.

Electric Drives Question 4:

Belt conveyors offer:

  1. High starting torque
  2. Medium starting torque
  3. Low starting torque
  4. Zero starting torque

Answer (Detailed Solution Below)

Option 1 : High starting torque

Electric Drives Question 4 Detailed Solution

  • Conveyor belts are used power plant industries as well as in any assembly line
  • Huge load is driven by the conveyor belt so the motor needs very high starting torque greater than their running torque
  • Three phase induction motors are used for these systems

Electric Drives Question 5:

Which part of the electric drive selects the motoring or braking mode of operation of the motor? 

  1. Source
  2. Load
  3. Motor
  4. Power modulator

Answer (Detailed Solution Below)

Option 4 : Power modulator

Electric Drives Question 5 Detailed Solution

The motoring or braking mode of operation of the electrical drive is decided by the power modulator.

Electrical Drive:
  • An electrical drive can be defined as an electromechanical device for converting electrical energy into mechanical energy to impart motion to different machines and mechanisms for various kinds of process control.
  • In other words, the system which is used for controlling the motion of an electrical machine, such type of system is called an electrical drive.
  • The block diagram of the electrical drive is shown in the figure below.
F5 Savita Engineering 20-9-22 D10
The main parts of the electrical drives are explained below in detail
Power Source:
  • The power source in the above block diagram offers the necessary energy for the system.
  • And both the converter and the motor interface with the power source to provide changeable voltage, frequency, and current to the motor.
Power Modulator: 
  • The power modulator regulates the output power of the source.
  • It controls the power from the source to the motor in such a manner that the motor transmits the speed-torque characteristic required by the load.
  • During the transient operations like starting, braking, and speed reversing the excessive current drawn from the source.
  • This excessive current drawn from the source may overload it or may cause a voltage drop.
  • Hence the power modulator restricts the source and motor current.
  • The power modulator converts the energy according to the requirement of the motor e.g. if the source is DC and an induction motor is used then the power modulator converts DC into AC.
  • It also selects the mode of operation of the motor, i.e., motoring or braking.
  • Types of Power Modulators:
    • Controlled rectifiers (AC to DC converters)
    • Inverters (DC to AC converters)
    • AC voltage controllers (AC to AC converters)
    • DC choppers (DC to DC converters)
    • Cycloconverters (frequency conversion)

Control Unit: 

  • The control unit controls the power modulator which operates at the small voltage and power levels.
  • The control unit also operates the power modulator as desired.
  • It also generates the commands for the protection of the power modulator and motor.
  • An input command signal which adjusts the operating point of the drive, from an input to the control unit.
Load:
  • The mechanical load can be decided by the environment of the industrial process & the power source can be decided by an available source at the place.
  • However, we can choose the other electric components namely the electric motor, controller, & converter.
Sensing Unit:
  • The sensing unit in the block diagram is used to sense the particular drive factor such as speed, and motor current.
  • This unit is mainly used for the operation of closed-loop otherwise protection.
Motor:
  • The electric motor intended for the specific application can be chosen by believing various features such as price, reaching the level of power & performance necessary by the load throughout the stable state as well as active operations.

Electric Drives Question 6:

Ward Leonard controlled D.C. drives are generally used for _________ excavators.

  1. Light duty 
  2. Medium duty
  3. Heavy duty
  4. Medium and heavy duty

Answer (Detailed Solution Below)

Option 3 : Heavy duty

Electric Drives Question 6 Detailed Solution

Ward Leonard controlled D.C. drives:

The speed control of DC motor accomplished by means of an adjustable voltage generator is called the Ward-Leonard system. If it is desired to have wide and very sensitive speed control, then this system is used.

This system is commonly employed for elevators, heavy-duty excavators, hoists and main drives in steel mills as this method can give unlimited speed control in either direction.

Electric Drives Question 7:

Which of the following can be used to hold the rotor of a 3 phase induction regulator in place?

  1. Worm gear
  2. Damper winding
  3. Compensator
  4. Starter

Answer (Detailed Solution Below)

Option 1 : Worm gear

Electric Drives Question 7 Detailed Solution

Concept:

Worm gear:

  • A worm gear is a gear including a shaft with a spiral section that engages with and runs a toothed wheel.
  • Worm gears are a traditional form of gear and a sort of one of the six simple machines.
  • Fundamentally, a worm gear is a screw butted up in front of what looks like a normal spur gear with slightly curved and angled teeth.

 

Worm Gear Uses:

  1. The first one is the great reduction ratio. A worm gear can have a high reduction ratio with small effort – all one should do is add margins to the wheel. Thus, you can utilize it to either greatly improve the torque or highly decrease the speed. It will commonly take several reductions of a conventional gearset to obtain the same reduction rate of a simple worm gear – meaning users of worm gears have fewer moving components and fewer spaces for failure.
  2. The second reason to employ a worm gear is the inability to reverse the power direction. Due to the friction between the wheel and the worm, it is effectively impossible for a wheel with the load applied to it to begin the worm moving.
  3. On a normal gear, the output and input can be changed independently when enough load is applied. This makes adding a backstop to a normal gearbox necessary, further raising the complication of the gear configuration.

Electric Drives Question 8:

Which of the following is NOT a type of transmission of drive?

  1. Horizontal drive
  2. Belt drive
  3. Rope drive
  4. Chain drive

Answer (Detailed Solution Below)

Option 1 : Horizontal drive

Electric Drives Question 8 Detailed Solution

Transmission of Power to Drive:

There are many ways of transmitting mechanical power developed by a motor to the driven machine.

1. Direct Drive:

  • In this case, the motor is coupled directly to the driven machine with the help of solid or flexible coupling.
  • Flexible coupling helps in protecting the motor from sudden jerks.
  • Direct drive is nearly 100% efficient and requires minimum space but is used only when the speed of the driven machine equals the motor speed.
     

2. Belt Drive:

  • Flat belts are extensively used for line-shaft drives and can transmit a maximum power of about 250 kW.
  • The minimum distance between the pulley centers should be 4 times the diameter of the larger pulley with a maximum ratio between pulley diameters of 6 : 1.
  • The power transmitted by a flat belt increases in proportion to its width and varies greatly with its quality and thickness.
  • There is a slip of 3 to 4 percent in the belt drive.
     

3. Rope Drive:

  • In this drive, a number of ropes are run in V-grooves over the pulleys.
  • It has a negligible slip and is used when the power to be transmitted is beyond the scope of belt drive.
     

4. Chain Drive:

  • Though somewhat more expensive, it is more efficient and is capable of transmitting larger amounts of power.
  • It is noiseless, slipless, and smooth in operation.
     

5. Gear Drive:

  • It is used when a high-speed motor is to drive a low-speed machine.
  • The coupling between the two is through a suitable ratio gearbox.
  • In fact motors for low-speed drives are manufactured with the reduction gear incorporated in the unit itself.

Electric Drives Question 9:

For Kiln drives, we don't use:

  1. Slip ring induction motor
  2. Squirrel cage motor
  3. Ward Leonard controlled DC motor
  4. Cascade controlled AC motor

Answer (Detailed Solution Below)

Option 2 : Squirrel cage motor

Electric Drives Question 9 Detailed Solution

Kiln Drives:

Rotary kiln drive is used in cement processing mills. The requirement of kiln drive depends on the type of Cement Mill Process (wet or dry). A variable-speed motor drives the pinion. 

The requirements of a kiln motor are the following:

  • Power requirement is high.
  • The speed control ratio is 1:10. Low creeping speeds of 1 rpm may be required.
  • Starting torque should be in the range of 200 to 250% of full load torque.
  • The acceleration of the drive should be completed in about 15 s.
  • For small periods an overload capacity of 200-250% may be required.
  • The motor must have suitable control for inching and spotting during maintenance.

 

The motors that meet the above requirements are as follows:

  1. A.C. motors with speed control.
  2. Slip ring induction motor.
  3. Ward Leonard controlled the D.C motor.
  4. Three-phased shunt-wound commutator motor.
  5. Cascade controlled A.C. motor.
  6. D.C. motor with transformer step switch control.

 

Conclusion: Since the squirrel cage induction motor starting torque is low as compared to the required torque, and also speed control is somewhat difficult. Hence, we can't use the Squirrel cage induction motor.

Electric Drives Question 10:

__________ is the method of braking, in which motor armature remains connected to the supply and draws power from it producing torque opposite to the direction of motion.

  1. Rheostatic braking
  2. Regenerative braking
  3. Plugging
  4. Eddy current braking

Answer (Detailed Solution Below)

Option 3 : Plugging

Electric Drives Question 10 Detailed Solution

Plugging:

  • In this method, the motor is reconnected to the supply in such a way that it has to develop torque in opposite direction to the movement of the rotor, it can be done by reversing the connections of the armature
  • The motor will decelerate until the speed is zero and then accelerates in opposite direction; Immediately, it is necessary to disconnect the motor from the supply as soon as the system comes to rest
  • The kinetic energy of the rotating parts of the motor is wasted and an additional amount of energy from the supply is required to develop the torque in the reverse direction, i.e. the motor should be connected to the supply during braking
  • It can be applied to both DC and AC motors

 

Regenerative braking:

  • In this method, no energy is drawn from the supply during the braking period and some of the energy fed back to the supply system
  • The braking torque generated in the motor is in the opposite direction of rotation of the rotor
  • It can be applied to both DC and AC motors

 

Dynamic braking:

For dynamic braking, the armature is disconnected from supply, and external resistance is connected so it is acting as a separately excited generator. Its stored kinetic energy converted into electrical energy and dissipated into the braking resistor.

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