Line Graph and Pie Chart MCQ Quiz in मल्याळम - Objective Question with Answer for Line Graph and Pie Chart - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക
Last updated on Mar 17, 2025
Latest Line Graph and Pie Chart MCQ Objective Questions
Top Line Graph and Pie Chart MCQ Objective Questions
Line Graph and Pie Chart Question 1:
The number of students passing of failing in an exam for a particular subject is presented in the bar chart above. Students who pass the exam cannot appear for the exam again. Students who fail the exam in the first attempt must appear for the exam in the following year. Students always pass the exam in their second attempt.
The number of students who took the exam for the first time in the year year 2 and the year 3 respectively, are ______
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 1 Detailed Solution
Given data from the chart,
|
Year |
Pass |
Fail |
Total |
|
1 |
50 |
10 |
60 |
|
2 |
60 |
5 |
65 |
|
2 |
50 |
3 |
53 |
Fail in the first year will give an exam in the second year.
Students will pass on 2nd attempt.
It means fail in 1st year students will become pass in 2nd year.
The number of students who took the exam for the first time in the year 2nd = 50 + 5 = 55
The number of students who took the exam for the first time in the year 3rd = 45 + 3 = 48
Line Graph and Pie Chart Question 2:
Comprehension:
Direction: Study the line graph and pie chart carefully to answer the following questions:
Total number of accidents over the 5 years = 5,00,000
Pie-chart represents the percentage of accidents over the 5 years.
The line graph the percentage of male accidents in 5 different years.
What is the percentage increase in the male accident in 2018 in comparison to 2015?
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 2 Detailed Solution
|
Years |
Total number of accidents |
Number of male accidents |
Number of female accidents |
|
2015 |
1,00,000 |
50,000 |
50,000 |
|
2016 |
1,50,000 |
45,000 |
1,05,000 |
|
2017 |
1,25,000 |
87,500 |
37,500 |
|
2018 |
75,000 |
60,000 |
15,000 |
|
2019 |
50,000 |
30,000 |
20,000 |
|
Total |
5,00,000 |
2,72,500 |
2,27,500 |
Number of total accidents in 2018 was (15/100) × 500000 = 75000
Percentage of the male accident in 2018 was 80%
⇒ Number of male accidents in 2018 was (80/100) × 75000 = 60000
Number of total accidents in 2015 was (20/100) × 500000 = 100000
Percentage of the male accident in 2015 was 50%
⇒ Number of male accidents in 2015 was (50/100) × 100000 = 50000
Required percent is [(60,000 – 50,000)/50,000] × 100
⇒ (10000/50000) × 100
⇒ 20%
∴ The percentage increase in the male accident in 2018 in comparison to 2015 is 20%.Line Graph and Pie Chart Question 3:
Comprehension:
Direction: There are various costs involved in the production of mobile phones. The pie-chart below shows the percentage of total cost spent on the production of each mobile. The line graph shows the number of 5 different models (A, B, C, D and E) of mobiles phones produced by a company. The percentage distribution of total cost is applicable to all models. Study the charts carefully and answer the questions.
Total cost spent on the components of all the mobiles of model D is Rs. 1.8 crores then find the machinery cost of each mobile of model D.
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 3 Detailed Solution
From the bar graph: Total 3000 mobiles of model D are produced.
Total cost spent on the components of all the mobiles of model D is Rs. 1.8 crores.
So,
Cost spent on the components of each mobile of model D = 18000000/3000
= Rs. 6000
Now,
From the pie chart:
Percentage of total cost spent on components = 40%
And
Percentage of total cost spent on machinery = 20%
Hence,
Machinery cost of each mobile of model D = 6000 × (20/40) = Rs. 3000Line Graph and Pie Chart Question 4:
Comprehension:
Direction∶ Study the following data and answer the question.
Data represent the number of students and the number of boys in each department.
One third of the difference between total number of boys and girls from civil, electrical and computer is approximately ______
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 4 Detailed Solution
For the number of boys,
Number of boys in Civil = 20% of 1300 = 0.2 × 1300 = 260
Number of boys in Electrical = 15% of 1300 = 195
Number of boys in Computer = 8% of 1300 = 104
Total number of boys in 3 department = 260 + 195 + 104 = 559
For the number of girls,
Number of girls in Civil = 320 – 260 = 60
Number of girls in Electrical = 250 – 195 = 55
Number of girls in Computer = 450 – 104 = 346
Total number of girls = 60 + 55 + 346 = 461
∴ Required difference = (559 – 461) /3 = 32.67 ≈ 33Line Graph and Pie Chart Question 5:
Comprehension:
Directions: Study the following table carefully and answer the questions given below it
The following graph shows the number of Men and Women (in ’00) working in different companies – A, B, C, D and E.
The following graph shows the percentage share of five cities in the total employees working in that company.
Note:
Total Employees = Men + Women
If, in Bangalore, the number of male employees working is 50% more than the number of female employees working, what is the number of female employees working in Bangalore?
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 5 Detailed Solution
Total number of employees working in five companies (in ’00)
⇒ 450 + 400 + 425 + 450 + 450 = 2175
Of these 217500 employees, 30% work in Bangalore.
Thus, Total number of employees working in Bangalore = 65,250.
Let,
Number of Female employees working in Bangalore = x
⇒ Number of Male employees working in Bangalore = 1.5x
∴ Total number of employees working in Bangalore = 2.5x
⇒ 2.5x = 65250
⇒ × = 26100
Thus,
Number of Females Working in Bangalore = 26100
Number of Males working in Bangalore = 39150Line Graph and Pie Chart Question 6:
Comprehension:
Following line graph and pie chart give information about speed and time travelled by 5 racers viz, Ram , Shyam, Raj, Suresh and Tarun.
Line Graph: The line graph shows the percentage difference (increase/decrease) of a particular racer, w.r.t to the previous racer. For example: Suresh- 30%, Suresh's speed is 30% more than the previous racer (Raj)
Total Distance travelled = 1950 km
Note: The values derived from line graph provide change in speed of racers. Also, time and distance travelled are given for one particular trip each racer did. Whenever speed is required, use average speed derived from line graph. Time and Distance need not be same as derived here, unless stated in the question.
Shyam is x km ahead of Ram and they are travelling in the same direction. Suresh is travelling in the opposite direction to them. Distance between Ram and Suresh being 810 km. Ram and Shyam start together, and after 1-hour Suresh starts traveling. As soon as Ram and Suresh meet, Shyam reverses his direction. If it takes Suresh 35 mins to cover the distance between them, find x.
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 6 Detailed Solution
Shyam's speed is 10% less than Ram's speed. Let's assume speed of Ram and Shyam as 10x and 9x respectively.
Raj's speed is 33.33% more than Shyam's speed. Raj's speed= (1 + 1/3) × 9x = 12x
Suresh speed= 25% more than Raj's speed= (1 + 1/4) × 12x = 15x
Tarun's speed= 16.67% less than Suresh's speed = (1 - 1/6) × 15x = (25/2)x.
Respective time taken by racers (from pie chart) = 8, 10, 5, 3, 4
Ram's distance = 8 × 10x = 80x
Shyam's distance = 10 × 9x = 90x
Raj's distance = 5 × 12x = 60x
Suresh's Distance = 15x × 3 = 45x
Tarun's Distance = 4 × (25x/2) = 50x
Total distance = (80 + 90 + 60 + 45 + 50)x = 325x
Total distance= 1950 (given)
325x = 1950
x = 6
Speeds = 60 km/hr, 54 km/hr, 72 km/hr , 90 km/hr and 75 km/hr
Distance between Ram and Suresh = 810 km
Distance travelled 1 hour after Ram started running = 810 - 1 × 60 = 750
Time taken for them to meet = 750/(60+90) = 5 hours.
Total Difference in distance travelled by Ram and Shyam = (60 - 54) × 6 = 36 km
Distance between Ram and Shyam when Ram meets Suresh= Distance travelled by Suresh to catch up after he meets Ram = (35/60) × (90 - 54) = (7/12) × 36 = 21 km
Initial Distance between Ram and Shyam = 36 - 21 = 15 km.Line Graph and Pie Chart Question 7:
Comprehension:
Directions: Study the following table carefully and answer the questions given below it
The following graph shows the number of Men and Women (in ’00) working in different companies – A, B, C, D and E.
The following graph shows the percentage share of five cities in the total employees working in that company.
Note:
Total Employees = Men + Women
If the number of women working in Company C in Hyderabad is 8000, what is the ratio of the number of men working in Company C in Hyderabad to the number of total employees working in Pune?
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 7 Detailed Solution
Given,
No. of women working in Company C in Hyderabad = 8000.
Total number of persons working in Company C = 15000 + 27500 = 42500
Of these 42500 employees, 25% of them work in Hyderabad.
∴ Total number of persons working in Company C in Hyderabad = 25% of 42500 = 10625
Of these 10625, 8000 are women.
∴ Number of Men working in Hyderabad in Company C = 10625 – 8000 = 2625
Total number of employees working in five companies (in ’00)
⇒ 450 + 400 + 425 + 450 + 450 = 2175
Of these 217500 employees, 10% work in Pune.
Thus, the number of employees from five companies working in Pune = 21750.
Required ratio = 2625 : 21750 = 525 : 4350 = 105 : 870 = 21 : 174 = 7 : 58
Line Graph and Pie Chart Question 8:
Comprehension:
Direction: There are various costs involved in the production of mobile phones. The pie-chart below shows the percentage of total cost spent on the production of each mobile. The line graph shows the number of 5 different models (A, B, C, D and E) of mobiles phones produced by a company. The percentage distribution of total cost is applicable to all models. Study the charts carefully and answer the questions.
The mobiles of model E are sold at 15% profit and the total profit earned by selling all the mobiles of model E is Rs. 84 lakhs. Find the cost spent on advertisement on each mobile of model E.
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 8 Detailed Solution
From the bar graph: Total 8000 mobiles of model E are produced.
So,
Amount of profit on each model = 8400000/8000 = Rs. 1050
Given: The mobiles of model E are sold at 15% profit
So,
Cost price of each mobile of model E = 1050/0.15 = Rs. 7000
From the pie chart:
Percentage of total cost spent on advertisement = 10%
Hence,
Cost spent on advertisement on each mobile of model E = 7000 × 0.1 = Rs. 700
Line Graph and Pie Chart Question 9:
Comprehension:
Direction: There are various costs involved in the production of mobile phones. The pie-chart below shows the percentage of total cost spent on the production of each mobile. The line graph shows the number of 5 different models (A, B, C, D and E) of mobiles phones produced by a company. The percentage distribution of total cost is applicable to all models. Study the charts carefully and answer the questions.
Total cost spent on Machinery for all the mobiles of model B is how much more than the total cost spent on Advertisement of all the mobiles of model E?
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 9 Detailed Solution
Line Graph and Pie Chart Question 10:
Comprehension:
Direction∶ Study the following data and answer the question.
Data represent the number of students and the number of boys in each department.
For the student of EC and Electrical, institute had planned a visit and collected Rs. 500 from each boy but girls need to pay is Rs. 200 only for this visit. The collected amount is utilized in travelling, food and water arrangement. The amount spent on traveling is 65%. The amount spent on water is Rs. ______
Answer (Detailed Solution Below)
Line Graph and Pie Chart Question 10 Detailed Solution
For the number of boys in EC,
Number of boys in EC = 12% of 1300 = 12 × 13 = 156
Number of girls in EC = 300 – 156 = 144
For the Electrical department,
Number of boys in Electrical = 15% of 1300 = 195
Number of girls in electrical = 250 – 195 = 55
For the total amount collected,
Amount collected by boys = (156 + 195) × 500 = Rs. 1,75,500
Amount collected by girls = (144 + 55) × 200 = Rs. 39,800
Total amount collected = 175500 + 39800 = Rs. 2,15,300
Amount spent on travelling = 65% of 215300 = 0.65 × 215300 = Rs. 1,39,945
Amount spent on food and water = 215300 – 139945 = Rs. 75,355
Now, no % had been given for food and water spending separately so, the data is insufficient