Error Analysis MCQ Quiz in मल्याळम - Objective Question with Answer for Error Analysis - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Last updated on Mar 16, 2025

നേടുക Error Analysis ഉത്തരങ്ങളും വിശദമായ പരിഹാരങ്ങളുമുള്ള മൾട്ടിപ്പിൾ ചോയ്സ് ചോദ്യങ്ങൾ (MCQ ക്വിസ്). ഇവ സൗജന്യമായി ഡൗൺലോഡ് ചെയ്യുക Error Analysis MCQ ക്വിസ് പിഡിഎഫ്, ബാങ്കിംഗ്, എസ്എസ്‌സി, റെയിൽവേ, യുപിഎസ്‌സി, സ്റ്റേറ്റ് പിഎസ്‌സി തുടങ്ങിയ നിങ്ങളുടെ വരാനിരിക്കുന്ന പരീക്ഷകൾക്കായി തയ്യാറെടുക്കുക

Latest Error Analysis MCQ Objective Questions

Top Error Analysis MCQ Objective Questions

Error Analysis Question 1:

The resistance of a circuit is found by measuring the current flowing and the power fed into the circuit. The limiting error of power and current measurement are found to be ± 2% and ± 1.25% respectively.

Which one of the following is the limiting error in the measurement of resistance?

  1. ± 4.5%
  2. ± 0.45%
  3. ± 2%
  4. ± 0.045%

Answer (Detailed Solution Below)

Option 1 : ± 4.5%

Error Analysis Question 1 Detailed Solution

We know that,

\(\begin{array}{l} P = {I^2}R\\ R = \frac{P}{{{I^2}}}\\ \% \frac{{dR}}{R} = \pm \left( {\frac{{dP}}{P} + 2\frac{{dI}}{I}} \right) \times 100 \end{array}\)

Given that,

\(\begin{array}{l} \frac{{dP}}{P} = 0.02,\frac{{dI}}{I} = 0.0125\\ \% \frac{{dR}}{R} = \pm \left( {0.02 + 2\left( {0.0125} \right)} \right) \times 100 \end{array}\)

= ± 4.5%

Alternate Method:

When variables are in division (or) in multiplication form, we can add the corresponding percentage limiting errors.

Given that,

Limiting error of P = ± 2%

Limiting error of I = ± 1.25%

Limiting error or R = ?

We know that, \(R = \frac{P}{{{I^2}}}\)

= ± 2% + 2 (± 1.25%)

= ± 4.5%

Error Analysis Question 2:

A voltage using a 20 microamp meter movement has a sensitivity of

  1. 20 micro ohm/volt
  2. 1000 ohm/volt
  3. 20,000 ohm/volt
  4. 50,000 ohm/volt

Answer (Detailed Solution Below)

Option 4 : 50,000 ohm/volt

Error Analysis Question 2 Detailed Solution

Concept:

In ammeters, the sensitivity \(S = \frac{1}{{{I_{fsd}}}}\)

Ifsd is the full-scale deflection in amps

It is expressed in ohm/volt

Calculation:

Full scale deflection = 20 μA

Sensitivity \(S = \frac{1}{{20 \times {{10}^{-6}}}} = 50,000\;ohm/volt\)

Error Analysis Question 3:

Repeatability and reproducibility are related to

  1. Accuracy of the instrument
  2. The precision of the instrument
  3. Both accuracy of the instrument & precision of the instrument
  4. None of these

Answer (Detailed Solution Below)

Option 2 : The precision of the instrument

Error Analysis Question 3 Detailed Solution

Precision: It is a measure of the reproducibility of the measurements, i.e. given a fixed value of quantity. It is a measure of the degree of agreement within a group of measurements.

Reproducibility: It is the degree of closeness with which given value may be repeatedly measured. It may be specified in terms of units for a given period of time.

Perfect reproducibility means that the instrument has no drift.

No drift means that with a given input the measured values do not vary with time.

Repeatability:

Reproducibility and repeatability are a measure of closeness with which a given input may be measured over and over again. Reproducibility is specified in terms of scale readings over a given period of time. Repeatability is defined as the variation of scale reading and is random in nature.

RRB JE EE 183 10Q RQBank 20 Hindi.docx 1

Repeatability and reproducibility are related to the precision of the instrument.

Error Analysis Question 4:

The errors mainly caused by human mistakes are

  1. Gross error
  2. Instrumental error
  3. Observational error
  4. Systematic error

Answer (Detailed Solution Below)

Option 1 : Gross error

Error Analysis Question 4 Detailed Solution

Gross Error

Systematic Error

Random Errors

1. These types of error mainly comprises of human mistakes in reading instruments and recording and calculating measurement results.

2. The experimenter is mainly responsible for these errors.

3. Some gross errors are easily detected while some are difficult to detect.

4. These errors can be avoided by taking great care in reading and recording the data. Also, two or three or even more readings should be taken for the quantity under measurement.

5. Computational mistakes, incorrect adjustment and improper application of instruments can lead to gross errors.

1. Systematic errors are classified into three types:

(i) Instruments Errors:

Occurs due to short coming in the instrument

Misuse of the instrument

Loading effect of the instrument

(ii) Environmental Errors:

These errors occur due to external environment factors like humidity, dust, vibrations or external magnetic field etc.

(iii) Observation Errors:

Different experimenters may produce different results, when sound and light measurements are involved since no two observers possess the same physical response.

1. Random errors are those errors whose causes can’t be established because of random variations in the parameters or the system of measurement.

2. The happenings or disturbances about which we are unaware are lumped together and called “Random” or “Residual” and error caused due to these happenings are called “Random” error.

Error Analysis Question 5:

Which errors arise due to the hysteresis of the equipment or due to friction?

  1. Observational Errors
  2. Random Error
  3. Environmental Error
  4. Instrumental Errors

Answer (Detailed Solution Below)

Option 4 : Instrumental Errors

Error Analysis Question 5 Detailed Solution

F1 S.B Madhu 24.12.19 D 10

Instrumentation Errors:

These errors arise due to three main reasons:

  • Instrumental errors occur due to the wrong construction of the measuring instruments.
  • These errors may occur due to hysteresis or friction.
  • These types of errors include the loading effect and misuse of the instruments.

 

Environmental Errors: These errors are due to conditions external to the measuring device including conditions in the area surrounding the instrument. These may be effects of temperature, pressure, humidity, dust, vibrations or of an external magnetic or electrostatic field.

Observational Errors: These types of errors occur due to wrong observations or reading in the instruments. The wrong observations may be due to parallax. In order to reduce the parallax error highly accurate meters are needed. Ex: meters provided with mirror scales.

Error Analysis Question 6:

Two resistances 100 Ω ± 5 Ω and 150 Ω ± 15 Ω are connected in series. If the deviations are standard deviations, the resultant resistance can be expressed as:

  1. 250 Ω ± 20 Ω
  2. 250 Ω ± 10 Ω
  3. 250 Ω ± 15.8 Ω
  4. 250 Ω ± 10.6 Ω

Answer (Detailed Solution Below)

Option 3 : 250 Ω ± 15.8 Ω

Error Analysis Question 6 Detailed Solution

R1 = 100 Ω ± 5 Ω

R2 = 150 Ω ± 15 Ω

R = R1 + R2

\(\begin{array}{l} \frac{{\partial R}}{{{R_1}}} = 1,\;{\sigma _1} = 5\\ \frac{{\partial R}}{{{R_2}}} = 1,\;{\sigma _2} = 15 \end{array}\)

Standard deviation of R is,

\(\sigma = \sqrt {{{\left( {\frac{{\partial R}}{{\partial {R_1}}}} \right)}^2}\sigma _1^2 + {{\left( {\frac{{\partial R}}{{\partial {R_2}}}} \right)}^2}\sigma _2^2}\)

\( = \sqrt {{{\left( 1 \right)}^2}{{\left( 5 \right)}^2} + {{\left( 1 \right)}^2}{{\left( {15} \right)}^2}} \)

= 15.8

Resultant resistance = 250 Ω ± 15.8 Ω 

Error Analysis Question 7:

The expected voltage value across an element is 50 V. However, a voltmeter reads it as 48 V. Calculate the percentage error in the measurement.

  1. 1%
  2. 2%
  3. 4%
  4. 3%

Answer (Detailed Solution Below)

Option 3 : 4%

Error Analysis Question 7 Detailed Solution

Error (E):

The difference of magnitude between measured value (Am) and true value (At) is called Error.

In engineering, the error is represented with ±.

In general, the error means Absolute Error it has only magnitude.

E = |Am - At|

Percentage error is given as

\(\%E=\frac{|A_m-A_t|}{A_t}\times 100=\frac{E}{A_t}\times 100\)

Application:

Given,

Am = 48 V

At = 50 V

From above concept,

E = |48 - 50| = 2 V

\(\%E=\dfrac{2}{50}\times100=4\ \%\)

Error Analysis Question 8:

Which of the following types of errors are dynamic errors?

  1. Human errors
  2. Observational errors
  3. Instrument errors caused due to slow response of instruments
  4. Environmental errors

Answer (Detailed Solution Below)

Option 3 : Instrument errors caused due to slow response of instruments

Error Analysis Question 8 Detailed Solution

The performance characteristics of an instrument are mainly divided into two categories: 

i) Dynamic characteristics 

ii) Static characteristics 

Dynamic characteristics: 

The set of criteria defined for the instruments, which are changing rapidly with time, is called ‘dynamic characteristics’. The various dynamic characteristics are:

 i) Speed of response

 ii) Measuring lag

 iii) Fidelity

iv) Dynamic error

Static characteristics: 

The set of criteria defined for the instruments, which are used to measure the quantities which are slowly varying with time or mostly constant, i.e., do not vary with time, is called ‘static characteristics’. 

The various static characteristics are: 

i) Accuracy  
ii) Precision  
iii) Sensitivity  
iv) Linearity  
v) Reproducibility  
vi) Repeatability  
viii) Threshold  
ix) Drift  
x) Stability  
xi) Tolerance  
xii) Range or span  

Error Analysis Question 9:

A.d.c. voltmeter has a sensitivity of 1000 Ω/Volt, When it measures half full scale in 100 V range, the current through the voltmeter will be:

  1. 50 mA
  2. 100 mA
  3. 1 mA
  4. 0.5 mA

Answer (Detailed Solution Below)

Option 4 : 0.5 mA

Error Analysis Question 9 Detailed Solution

Voltmeter Sensitivity (Sv):

The voltmeter sensitivity is determined by dividing the sum of the resistance of the meter (Rm), plus the series resistance (Rs), by the full-scale reading in volts.

Mathematically, sensitivity is expressed as:

\(S_v=\frac{R_m+R_s}{E}\)

Expressing the above expression in units, we get:

\(S_v=\frac{Ohms}{Volt}\)

Voltmeter sensitivity is expressed in Ohm/Volt

Sensitivity is also expressed as:

\(S_v=\frac{1}{I_{FSD}}\)

So, sensitivity is said to be equal to the reciprocal of the full-scale deflection current.

Application:

Sensitivity, Sv = 1000 Ω/V

\({{\rm{I}}_{{\rm{FSD}}}} = \frac{1}{{\rm{S_v}}} = \frac{1}{{1000}} = 1{\rm{mA}}\)

At half full scale the current reading will be = 0.5 mA

Error Analysis Question 10:

A 0 – 300 V voltmeter has a guaranteed accuracy of 2% full – scale reading (deflection). The voltage measured by this instrument is 200 V. The limiting error is given by:

  1. 2%
  2. 3%
  3. 2.5%
  4. 3.5%

Answer (Detailed Solution Below)

Option 2 : 3%

Error Analysis Question 10 Detailed Solution

Full scale voltage = 300 V

Accuracy = 2%

Voltage to be measured = 200 V

The limiting error is given as :-

\(\frac{2}{{100}} \times 300 \times \frac{1}{{200}}\)

= 6/200

2% of limiting error

\(\frac{6}{{200}} \times 100 = 3\% \)

OR
\(\)Limiting error= \(\frac {\%Guaranteed\ accuracy\times FSR}{Measured\ value}\)\( \frac{2\times300}{200}=3\%\)

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