Diode Rectifiers MCQ Quiz in मल्याळम - Objective Question with Answer for Diode Rectifiers - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

In a three-phase diode bridge rectifier, the average output $\left(V_0\right)=\frac{3V_{mL}}{\pi }$

And V₀ = RI₀ + E

RMS value of the fundamental component of source current is,

$I_{s1}=\frac{\sqrt{6}}{\pi }{I}_0$

Given that, supply voltage (V_rms) = 440 V

Maximum line voltage (V_mL) $=440\sqrt{2}V$

Average output voltage $\left(V_0\right)=\frac{3\times 440\sqrt{2}}{\pi }=594.21V$

$I_0=\frac{V_0-E}{R}=\frac{594.21-220}{8}=46.78A$

RMS value of the fundamental component of source current,