Vapour Compression (V-C) Cycle MCQ Quiz - Objective Question with Answer for Vapour Compression (V-C) Cycle - Download Free PDF
Last updated on May 30, 2025
Latest Vapour Compression (V-C) Cycle MCQ Objective Questions
Vapour Compression (V-C) Cycle Question 1:
The centrifugal compressor in vapour compression refrigeration system is very sensitive to
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 1 Detailed Solution
Explanation:
Centrifugal Compressor:
- A centrifugal compressor is a dynamic compressor used in various refrigeration systems. It operates by converting the kinetic energy of a fluid into pressure energy via a rotating impeller. In a vapour compression refrigeration system, the centrifugal compressor is critical for compressing refrigerant vapour to a higher pressure and temperature, enabling heat rejection at the condenser.
Working Principle: The centrifugal compressor works by accelerating the refrigerant vapour using a high-speed impeller. The velocity of the refrigerant increases as it passes through the impeller, and this kinetic energy is then converted into pressure energy in the diffuser. The resulting pressurized refrigerant vapour is sent to the condenser for heat rejection.
The centrifugal compressor's performance in a vapour compression refrigeration system is highly sensitive to both the evaporator temperature and the condenser temperature. Here’s why:
- Evaporator Temperature: The evaporator temperature determines the pressure at which the refrigerant enters the centrifugal compressor. Lower evaporator temperatures correspond to lower suction pressures. If the suction pressure drops too much, the compressor may face issues such as surge, reduced efficiency, or stalling. Additionally, the refrigerant density at the inlet is affected, which influences the compressor’s capacity.
- Condenser Temperature: The condenser temperature determines the discharge pressure of the compressor. Higher condenser temperatures correspond to higher discharge pressures. If the discharge pressure is excessively high, the compressor requires more work, increasing power consumption and potentially causing mechanical stress or operational instability.
Thus, the centrifugal compressor's operation is intricately linked to both the evaporator and condenser temperatures, as these parameters significantly affect the suction and discharge pressures, refrigerant density, and overall compressor efficiency. A balanced and stable operation of the refrigeration system necessitates keeping both temperatures within optimal ranges to ensure efficient and reliable compressor performance.
Vapour Compression (V-C) Cycle Question 2:
The flash chamber in vapour compression cycle (Single stage) is incorporated to
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 2 Detailed Solution
Explanation:
The Flash Chamber in Vapour Compression Cycle (Single Stage)
Definition: In a vapour compression refrigeration system, the flash chamber is a component that is used to separate the liquid and vapour phases of the refrigerant after the expansion valve. It is typically employed to improve the system's performance by managing the refrigerant's phase before it enters the evaporator.
Function of the Flash Chamber: The primary function of the flash chamber is to separate the liquid refrigerant from the vapour refrigerant. The liquid refrigerant, which has the desired cooling effect, is directed towards the evaporator, while the vapour refrigerant is bypassed to the compressor. This separation ensures that only the liquid refrigerant flows into the evaporator, optimizing its performance and reducing the load on the compressor.
Importance of Incorporating a Flash Chamber:
- Improved Efficiency: By ensuring that only liquid refrigerant enters the evaporator, the flash chamber enhances the heat transfer efficiency and maximizes the refrigerating effect.
- Reduced Compressor Work: The flash chamber prevents vapour refrigerant from entering the evaporator, thereby reducing the load on the compressor and improving the system's overall efficiency.
- System Protection: It prevents vapour refrigerant from inadvertently entering the evaporator, which could lead to inefficiencies or damage to the system components.
Reduce the size of the evaporator
- The flash chamber in a vapour compression cycle helps reduce the size of the evaporator. By separating the liquid refrigerant from the vapour refrigerant and ensuring that only liquid enters the evaporator, the flash chamber allows for a more compact and efficient evaporator design. Since the heat transfer in the evaporator is optimized, the size of the evaporator can be reduced without compromising the system's performance.
Vapour Compression (V-C) Cycle Question 3:
In a vapour compression system, the condition of refrigerant is dry saturated vapour
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 3 Detailed Solution
Concept:
Vapor Compression Refrigeration System:
Processes in the vapor compression system:
- Process 1-2: Isentropic compression of saturated vapor in the compressor.
- Process 2-3: Isobaric heat rejection in the condenser.
- Process 3-4: Isenthalpic expansion of the saturated liquid in the expansion device.
- Process 4-1: Isobaric heat extraction in the.
- In a vapor compression system, the condition of refrigerant before entering the compressor is the dry saturated vapor as shown in the figure at point '1'.
- At the end of the compressor or entry point of the condenser, the state of refrigerant is Superheated vapor.
- At the end of the condenser or entry point of the throttling valve, the state of refrigerant is Saturated liquid.
Vapour Compression (V-C) Cycle Question 4:
The higher and lower temperature in refrigerator working on reversed carnot cycle are 35°C and - 15°C. The capacity of the machine is 35.16 kW. Calculate the coefficient of performance (COP).
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 4 Detailed Solution
Explanation:
COP of a Carnot refrigerator:
COP = TL / (TH - TL)
Where:
TL = Lower temperature (in Kelvin)
TH = Higher temperature (in Kelvin)
First, convert the temperatures from Celsius to Kelvin:
- TH = 35ºC = 35 + 273 = 308 K
- TL = -15ºC = -15 + 273 = 258 K
Now, substitute the values into the COP formula:
COP = 258 / (308 - 258)
COP = 258 / 50
COP = 5.16
Vapour Compression (V-C) Cycle Question 5:
Identify the cycle on the basis of its P-h diagram.
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 5 Detailed Solution
Explanation:
Vapour Compression Refrigeration Cycle
- The vapour compression refrigeration cycle is a widely used method for air conditioning, refrigeration, and heat pump systems. It operates by compressing a refrigerant, condensing it to release heat, expanding it to absorb heat, and then evaporating it to complete the cycle. This process transfers heat from a lower temperature space to a higher temperature space, thereby providing cooling.
Working Principle: The vapour compression refrigeration cycle involves four main components: the compressor, condenser, expansion valve, and evaporator. The process can be described in the following steps:
- Compression: The refrigerant enters the compressor as a low-pressure vapour. The compressor raises the pressure and temperature of the refrigerant, turning it into a high-pressure, high-temperature vapour.
- Condensation: The high-pressure vapour flows into the condenser, where it releases its heat to the surrounding environment and condenses into a high-pressure liquid.
- Expansion: The high-pressure liquid refrigerant passes through the expansion valve, where its pressure is reduced, causing it to expand and cool down, partially evaporating into a low-pressure liquid-vapour mixture.
- Evaporation: The low-pressure mixture enters the evaporator, where it absorbs heat from the space to be cooled, fully evaporating into a low-pressure vapour. This low-pressure vapour then returns to the compressor, completing the cycle.
Top Vapour Compression (V-C) Cycle MCQ Objective Questions
Domestic refrigerator working on vapour compression cycle uses the following type of expansion device
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 6 Detailed Solution
Download Solution PDFConcept:
- The capillary tube is one of the most commonly used throttling devices in the domestic refrigerators, deep freezers, water coolers, and air conditioners.
- Capillary tubes have very small internal diameters and very long length and they are coiled to several turns so that it would occupy less space (compact).
- They are easy to manufacture, cheap and compact.
Working:
- When the refrigerant leaves the condenser and enters the capillary tube, its high pressure drops down suddenly due to the very small diameter of the capillary tube and the long length gives more friction head and drops pressure further.
- The decrease in pressure leads to cooling of refrigerant and the low-temperature refrigerant can take the heat from the room.
The lowest temperature during the cycle in a vapour compression system occurs after
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 7 Detailed Solution
Download Solution PDFExplanation:
Vapour Compression Refrigeration System:
The four processes in simple VCRS include:
- Isentropic compression (1-2) in Compressor.
- Constant Pressure heat removal (2-3) in Condensor.
- Isenthalpic expansion (3-4) in a Throttling device.
- Constant pressure heat removal (4-1) in Evaporator.
From the Above T-s diagram, we can conclude that the lowest temperature during the cycle in a vapour compression system occurs after expansion and during the evaporation process(4-1) in the evaporator.
In the Question the exact location of the lowest temperature has not been asked here they have asked after which process the lowest temperature will be obtained. The lowest temperature surely is obtained in the evaporator which comes after the expansion process hence the expansion is the correct answer.
In P-H diagram of vapour compression refrigeration cycle, the compression process is shown by a:
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 8 Detailed Solution
Download Solution PDFExplanation:
The vapor-compression cycle is a process used to extract heat from a box or a room that underlies most refrigeration and air conditioning techniques. It consists of four separate stages:
- Compression(1-2) Isentropic Compression
- Condensation(2-3) Heat rejection at constant pressure
- Expansion(3-4) Constant enthalpy expansion
- Evaporation (4-1) Constant pressure heat addition
The T-s and P-h diagram is shown in the figure below.
Referring to the above diagram, the P-H diagram of the vapor compression refrigeration cycle, the compression process is shown by a straight line with a positive slope
Additional Information
The diagram given is the P-h diagram as it is similar to the P-h diagram drawn as per the process occurring from 1-2-3-4-1 in the cycle.
Refrigeration effect = R.E = mas flow rate × (enthalpy at evaporator exit – enthalpy at condenser exit)
Refrigeration effect = ṁ × (h1 - h4)
and \(COP =\frac{h_1-h_4}{h_2-h_1}\)
The refrigerant used in the VCR based refrigerant cycle rejects heat at __________.
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 9 Detailed Solution
Download Solution PDFExplanation:
- Process 1-2: Reversible adiabatic compression.
- Process 2-3: Constant pressure heat rejection.
- Process 3-4: Irreversible expansion (throttling).
- Process 4-1: Constant pressure heat addition.
Working in Vapour Compression Refrigeration System:
- The refrigerant in a liquid state absorbs heat from the evaporator and converted it into vapour form.
- The refrigerant in vapour form enters the compressor where temperature and pressure increased by compressing vapour.
- In Condensor due to temperature difference heat rejected to the atmosphere.
- In Expansion device due to throttling process temperature and pressure drops by maintaining constant enthalpy.
The heat rejection factor in vapour compression refrigeration system will be
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 10 Detailed Solution
Download Solution PDFExplanation:
Vapour Compression Refrigeration Cycle:
Process 1-2: Isentropic Work Done by Compressor
Process 2-3: Constant Pressure Heat Removal by Condenser
Process 3-4: Isentropic Expansion by Throttling Valve
Process 4-1: Constant Pressure Heat Addition by Evaporator
From the Heat Balance Equation:
Energy transferred from Condenser = Energy Transferred to Evaporator + Work Input to the compressor
Heat rejection ratio is given by:
\({\rm{HRR}} = 1 + \frac{1}{{{\rm{COP}}}} = 1 + \frac{W_{input}}{{{\rm{RE}}}} =\frac{{{{\rm{Q}}_{{\rm{COND}}}}}}{{{\rm{RE}}}}\)
Or
\({\rm{HRR}} = {\rm{Heat\;rejection\;ratio}} = \frac{{{{\rm{Q}}_{\rm{COND}}}}}{{{{\rm{RE}}}}}\)
Where,
QCOND is heat rejected in the condenser,
RE is the Refrigeration effect and Winput is the work input to the Refrigeration System
Heat rejected in the condenser is always more than heat absorbed in the evaporator.
So, the heat rejection factor in vapour compression refrigeration system will be more than one.
The COP of a one-ton VCC refrigerating machine is 3.5. The minimum power needed to run this machine would be
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 11 Detailed Solution
Download Solution PDFConcept:
Here, VCC stands for Vapour Compression Cycle.
For refrigeration cycle:
\(COP = \frac{{Refrigeration\;capacity}}{{Power\;supplied}}\)
Calculation:
Given:
COP = 3.5, Refrigeration capacity = 1 Ton = 3.5 kW
\(COP = \frac{{Refrigeration\;capacity}}{{Power\;supplied}}\)
we can rearrange it as
\(Power\;supplied = \frac{{Refrigeration\;capacity}}{{COP}}\)\( = \frac{{3.5}}{{3.5}}\) = 1 kW
Hence the minimum power needed to run this machine would be 1 kW.
A domestic refrigerator works on the:
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 12 Detailed Solution
Download Solution PDFExplanation:
Vapour Compression Cycle
The vapour-compression cycle is a process used to extract heat from a box or a room that underlies most refrigeration and air conditioning techniques. It consists of four separate stages:
- Compression(1-2)
- Condensation(2-3)
- Expansion(3-4)
- Evaporation (4-1)
And in the domestic refrigerator, the purpose is to extract the heat from the refrigerator hence it follows the vapour compression cycle
a) Basic vapour compression b) T-s diagram c) p-h diagram
refrigeration system
*Trick to remember –Most of you will get confused that whether it works on vapour compression cycle or the vapour absorption cycle. So here is a simple trick to remember. You might have noticed a compressor installed at the back of our domestic refrigerator that’s it because the cycle on which it works is vapour compression cycle.
In a vapor compression refrigeration system, the sub-cooling of refrigerant in the condenser results in:
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 13 Detailed Solution
Download Solution PDFExplanation:
- Sub cooling is the process of cooling the liquid refrigerant below the condensing temperature for a given pressure.
- The difference between the saturation temperature and the temperature of sub cooled liquid at that pressure is called Degree of sub cooling.
- Subcooling is beneficial as it increases the refrigeration effect by reducing the throttling loss at no additional specific work input.
- Also, subcooling ensures that only liquid enters the throttling device leading to its efficient operation.
Effect of Sub cooling:
- Increase the refrigeration effect
- Work input remains same
- Increase in COP
As the Subcooling increases the refrigeration effect, Hence to produce more refrigeration evect a larger size evaporator will be required. Hence subcooling of the refrigerant in condenser increases the evaporator size.
In a refrigeration system, subcooling
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 14 Detailed Solution
Download Solution PDFConcept:
Subcooling is the process of cooling the liquid refrigerant below the condensing temperature for a given pressure.
The difference between the saturation temperature and the temperature of the subcooled liquid at that pressure is called the Degree of subcooling.
Subcooling is beneficial as it increases the refrigeration effect by reducing the throttling loss at no additional specific work input.
Also, subcooling ensures that only liquid enters the throttling device leading to its efficient operation.
Effect of Subcooling:
- Increase the refrigeration effect
- Work input remains the same
- Increase in COP
1 ton of refrigeration is equal to:
Answer (Detailed Solution Below)
Vapour Compression (V-C) Cycle Question 15 Detailed Solution
Download Solution PDFConcept:
Units of refrigeration are commonly defined in terms of a ton of refrigeration.
One ton of refrigeration is defined as the capacity to freeze one tone of water at 0°C into ice in 24 hours.
1 TR (Ton of refrigeration) = 210 kJ/min = 3.5 kW