Single Level MCQ Quiz - Objective Question with Answer for Single Level - Download Free PDF
Last updated on Apr 9, 2025
Latest Single Level MCQ Objective Questions
Single Level Question 1:
Consider a computer system with 48 bit virtual addressing and page size of 16 KB. If the system has one level page table per process and each page table entry requires 32 bits, then the size of the page table is ___________.
Answer (Detailed Solution Below)
Single Level Question 1 Detailed Solution
Data
Logical address = 248 B
page size = 214 KB
page table entry (PTE) = 32 bits
Formula:
Page table size (PTS) = number of pages × PTE
Calculation:
number of pages = \({2^{48} \over {2^{14}}}\)
PTS = 234 × 32 bits = 239 bits = 512 Gb
Important Points:
b → bits
1 G→ 230
Top Single Level MCQ Objective Questions
Single Level Question 2:
Consider a computer system with 48 bit virtual addressing and page size of 16 KB. If the system has one level page table per process and each page table entry requires 32 bits, then the size of the page table is ___________.
Answer (Detailed Solution Below)
Single Level Question 2 Detailed Solution
Data
Logical address = 248 B
page size = 214 KB
page table entry (PTE) = 32 bits
Formula:
Page table size (PTS) = number of pages × PTE
Calculation:
number of pages = \({2^{48} \over {2^{14}}}\)
PTS = 234 × 32 bits = 239 bits = 512 Gb
Important Points:
b → bits
1 G→ 230
Single Level Question 3:
\(\begin{align*} &\textbf{A)} \text{ If } \frac{1}{x} : \frac{1}{y} : \frac{1}{z} = 2 : 3 : 5, \text{ then } x : y : z = 15 : 10 : 6 \\ &\textbf{B)} \text{ If } 4p = 6q = 9r, \text{ then } p : q : r = 9 : 6 : 4 \\ &\textbf{C)} \text{ If } 2A = 3B = 4C, \text{ then } A : B : C = 3 : 4 : 6 \\ &\textbf{D)} \text{ If } P : Q : R = 2 : 3 : 4, \text{ then } \frac{P}{Q} : \frac{Q}{R} : \frac{R}{P} = 9 : 8 : 24 \end{align*}\)
Choose the correct answer from the options given below
Answer (Detailed Solution Below)
Single Level Question 3 Detailed Solution
A:
Given: \( \frac{1}{x} : \frac{1}{y} : \frac{1}{z} = 2 : 3 : 5 \)
To find: \( x : y : z \)
We invert the terms: \( x : y : z = \frac{1}{2} : \frac{1}{3} : \frac{1}{5} = \frac{15}{30} : \frac{10}{30} : \frac{6}{30} = 15 : 10 : 6 \)
Correct
B:
Given: \( 4p = 6q = 9r \)
Let the common value be \( k \).
Then, \( p = \frac{k}{4} \), \( q = \frac{k}{6} \), and \( r = \frac{k}{9} \)
So, \( p : q : r = \frac{k}{4} : \frac{k}{6} : \frac{k}{9} \)
Multiply all terms by 36: \( = 9k : 6k : 4k = 9 : 6 : 4 \)
Correct
C:
Given: \( 2A = 3B = 4C \)
Let the common value be \( k \).
Then, \( A = \frac{k}{2} \), \( B = \frac{k}{3} \), and \( C = \frac{k}{4} \)
So, \( A : B : C = \frac{k}{2} : \frac{k}{3} : \frac{k}{4} = \frac{6k}{12} : \frac{4k}{12} : \frac{3k}{12} = 6 : 4 : 3 \)
Incorrect (the assumed ratio 3 : 4 : 6 was wrong)
D:
Given: \( P : Q : R = 2 : 3 : 4 \)
To find: \( \frac{P}{Q} : \frac{Q}{R} : \frac{R}{P} \)
Let \( P = 2k \), \( Q = 3k \), and \( R = 4k \)
Now, \( \frac{P}{Q} = \frac{2k}{3k} = \frac{2}{3} \), \( \frac{Q}{R} = \frac{3k}{4k} = \frac{3}{4} \), \( \frac{R}{P} = \frac{4k}{2k} = 2 \)
So, \( \frac{P}{Q} : \frac{Q}{R} : \frac{R}{P} = \frac{2}{3} : \frac{3}{4} : 2 \)
Multiply all by 12: \( = 8 : 9 : 24 \)
Incorrect (the assumed ratio 9 : 8 : 24 was wrong)