Single Level MCQ Quiz - Objective Question with Answer for Single Level - Download Free PDF

Last updated on Apr 9, 2025

Latest Single Level MCQ Objective Questions

Single Level Question 1:

Consider a computer system with 48 bit virtual addressing and page size of 16 KB. If the system has one level page table per process and each page table entry requires 32 bits, then the size of the page table is ___________.

  1. 512 Gb
  2. 512 Mb
  3. 512 KB
  4. 1024 MB

Answer (Detailed Solution Below)

Option 1 : 512 Gb

Single Level Question 1 Detailed Solution

Data

Logical address = 248  B

page size = 214 KB 

page table entry (PTE) = 32 bits

Formula:

Page table size (PTS) = number of pages × PTE

Calculation:

number of pages = \({2^{48} \over {2^{14}}}\)

PTS = 234 × 32 bits = 239 bits = 512 Gb

Important Points:

b → bits

1 G→  230

Top Single Level MCQ Objective Questions

Single Level Question 2:

Consider a computer system with 48 bit virtual addressing and page size of 16 KB. If the system has one level page table per process and each page table entry requires 32 bits, then the size of the page table is ___________.

  1. 512 Gb
  2. 512 Mb
  3. 512 KB
  4. 1024 MB

Answer (Detailed Solution Below)

Option 1 : 512 Gb

Single Level Question 2 Detailed Solution

Data

Logical address = 248  B

page size = 214 KB 

page table entry (PTE) = 32 bits

Formula:

Page table size (PTS) = number of pages × PTE

Calculation:

number of pages = \({2^{48} \over {2^{14}}}\)

PTS = 234 × 32 bits = 239 bits = 512 Gb

Important Points:

b → bits

1 G→  230

Single Level Question 3:

\(\begin{align*} &\textbf{A)} \text{ If } \frac{1}{x} : \frac{1}{y} : \frac{1}{z} = 2 : 3 : 5, \text{ then } x : y : z = 15 : 10 : 6 \\ &\textbf{B)} \text{ If } 4p = 6q = 9r, \text{ then } p : q : r = 9 : 6 : 4 \\ &\textbf{C)} \text{ If } 2A = 3B = 4C, \text{ then } A : B : C = 3 : 4 : 6 \\ &\textbf{D)} \text{ If } P : Q : R = 2 : 3 : 4, \text{ then } \frac{P}{Q} : \frac{Q}{R} : \frac{R}{P} = 9 : 8 : 24 \end{align*}\) 
 Choose the correct answer from the options given below

  1.  (C) only
  2. (D) only
  3. (A) and (B) only
  4.  (C) and (D) only

Answer (Detailed Solution Below)

Option 3 : (A) and (B) only

Single Level Question 3 Detailed Solution

A:

Given: \( \frac{1}{x} : \frac{1}{y} : \frac{1}{z} = 2 : 3 : 5 \)

To find: \( x : y : z \)

We invert the terms: \( x : y : z = \frac{1}{2} : \frac{1}{3} : \frac{1}{5} = \frac{15}{30} : \frac{10}{30} : \frac{6}{30} = 15 : 10 : 6 \)

Correct

B:

Given: \( 4p = 6q = 9r \)

Let the common value be \( k \).

Then, \( p = \frac{k}{4} \), \( q = \frac{k}{6} \), and \( r = \frac{k}{9} \)

So, \( p : q : r = \frac{k}{4} : \frac{k}{6} : \frac{k}{9} \)

Multiply all terms by 36: \( = 9k : 6k : 4k = 9 : 6 : 4 \)

Correct

C:

Given: \( 2A = 3B = 4C \)

Let the common value be \( k \).

Then, \( A = \frac{k}{2} \), \( B = \frac{k}{3} \), and \( C = \frac{k}{4} \)

So, \( A : B : C = \frac{k}{2} : \frac{k}{3} : \frac{k}{4} = \frac{6k}{12} : \frac{4k}{12} : \frac{3k}{12} = 6 : 4 : 3 \)

Incorrect (the assumed ratio 3 : 4 : 6 was wrong)

D:

Given: \( P : Q : R = 2 : 3 : 4 \)

To find: \( \frac{P}{Q} : \frac{Q}{R} : \frac{R}{P} \)

Let \( P = 2k \), \( Q = 3k \), and \( R = 4k \)

Now, \( \frac{P}{Q} = \frac{2k}{3k} = \frac{2}{3} \), \( \frac{Q}{R} = \frac{3k}{4k} = \frac{3}{4} \), \( \frac{R}{P} = \frac{4k}{2k} = 2 \)

So, \( \frac{P}{Q} : \frac{Q}{R} : \frac{R}{P} = \frac{2}{3} : \frac{3}{4} : 2 \)

Multiply all by 12: \( = 8 : 9 : 24 \)

Incorrect (the assumed ratio 9 : 8 : 24 was wrong)

Get Free Access Now
Hot Links: teen patti fun teen patti master update teen patti online teen patti pro teen patti lucky